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2 years ago

A bag contains 10 black marbles and 6 red marbles. If a red

Mathematics

1 answer:

bonufazy [111]2 years ago

7 0

Answer:

66.67% probability of selecting a black marble from the bag.

Step-by-step explanation:

Initially there are 16 marbles, 10 of which are black and 6 of which are red.

A red marble is drawn and not put back. So now there are 15 marbles, of which 10 are black.

So there is a 10/15 = 2/3 = 0.666% 7 = 66.67% probability of selecting a black marble from the bag.

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Which of the following is the solution to the differentiable equation dy/dx=4x/y, where Y(2)=-2

aliya0001 [1]

First we'll substitute $\frac{dy}{dx}$ with $y'$

$y'=\frac{4x}{y}$

Then we can separate this.

$yy'=4x$

Then we'll solve this.

$yy'=4x: \frac{y^2}{2}=2x^2+c_1$

$\frac{y^2}{2}=2x^2-6$

$y=2\sqrt{x^2-3},y=-2\sqrt{x^2-3}$

Then we'll plug in to find the extraneous solutions (if any)

$y=-2\sqrt{x^2-3}$

7 0

3 years ago

56 is 80 percent of what number

monitta

Let us assume the number to be = x
Then
(80/100) * x = 56
4x/5 = 56
4x = 56 * 5
4x = 280
x = 280/4
= 70
The value of the unknown number is 70. I hope the procedure is clear enough for you to understand. You can always use this method for solving similar problems in future without requiring any help from outside. Only thing that needs to be taken care of is the calculation part.

7 0

2 years ago

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Aleonysh [2.5K]

Answer:

Step-by-step explanation:

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3 years ago

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I cant believe how bad my brother, Reuben, is at growing things. He bought a whole bunch of plants at the nursery the other day.

jeka94

Answer:

68 plants.

Step-by-step explanation:

Let x represent the number of plants that Reuben bought from the nursery.

We have been given that Reuben bought a whole bunch of plants at the nursery the other day. Right away, five died. So number of plant left would be $x-5$ .

We are also told that then our dog dug up 2/9 of them. So number of plants left after dug-up would be $\frac{2}{9}(x-5)$ .

Further a rabbit came and ate ½ of what was left. So number of plants left would be $\frac{\frac{2}{9}(x-5)}{2}=\frac{2}{9\times 2}(x-5)=\frac{1}{9}(x-5)$ .