Part A:
Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4
The perimeter of the square is given by 4(x + 4) = 4x + 16
The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12
For the perimeters to be the same
4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2
The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.
Part B:
The area of the square is given by

The area of the rectangle is given by 2(3x + 4) = 6x + 8
For the areas to be the same

Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
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Answer: Irrational because cannot be turned into fractions
Step-by-step explanation:
Hope this helps...feel free to ask for any help
<span>Plan 1: $50 for a monthly pass and a $3 fee for each gym visit
So, the monthly pass is 50 plus 3 for each visit. You know 50 stays constant no matter how much Hayley goes to the gym so you can already put that into the form as 'b' also known as the y-intercept.
y=mx+50
Now, you need to find the slope which is the amount it increases or decreases by every time. Since Hayley gets charged $3 every visit, that would be the slope (m).
Plan 1: y=3x+50
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Plan 2: $10 for each gym visit
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There is only a slope (m) for this. Technically there is a y-intercept (b), but since that is 0 it is not needed. Plug in the values.
y=mx+b
y=10x