1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anika [276]
3 years ago
12

Write a program that will generate 100 integers between 0 and 1000. Store the even numbers in a sorted linked list called evens.

Store the odd numbers in a different sorted linked list called odds. Print the content of the evens and odds linked lists to the screen. Use the Linked_List class we developed in class.
Computers and Technology
1 answer:
Tomtit [17]3 years ago
8 0

Answer:

see explaination

Explanation:

import random

def num_gen(s, e, n):

r = []

for j in range(n):

r.append(random.randint(s, e))

return r

n = 100

s = 0

e = 1000

l = num_gen(s, e, n)

even_list = []

odd_list = []

for i in l:

if i % 2 == 0:

even_list.append(i)

else:

odd_list.append(i)

print("Even List:", even_list)

print("Odd List:", odd_list)

You might be interested in
_______ integrates all departments and functions throughout an organization into a single IT system (or integrated set of IT sys
aleksklad [387]

Answer:

ERP ( Enterprise Resource Planning )

Explanation:

ERP mainly stands for enterprise resource planning. ERP is system software which is a combination of many application which works together to automate a business process.  

It is a business management software which reduces the wastage of time by making tasks simpler like when we talk about accounting and stock in a company, it takes very much time when maintaining by humans but when it comes to ERP software, it only takes a while to give you detailed information about everything. It automates the manual process of a company and gives speed to the growth of the company.

3 0
3 years ago
Ms. Osteen gives her class an assignment to insert background color that gradually changes from blue to green. To accomplish thi
irina1246 [14]

Answer:

C

Explanation:

7 0
3 years ago
Write a program that calculates payments for loan system. Implement for both client and Server. - The client sends loan informat
egoroff_w [7]

Answer:

Check the explanation

Explanation:

//Define the class.

public class Loan implements java.io.Serializable {

 

//Define the variables.

private static final long serialVersionUID = 1L;

private double annualInterestRate;

private int numberOfYears;

private double loanAmount;

private java.util.Date loanDate;

//Define the default constructor.

public Loan() {

this(2.5, 1, 1000);

}

//Define the multi argument constructor.

protected Loan(double annualInterestRate, int numberOfYears,

double loanAmount) {

this.annualInterestRate = annualInterestRate;

this.numberOfYears = numberOfYears;

this.loanAmount = loanAmount;

loanDate = new java.util.Date();

}

//Define the getter and setter method.

public double getAnnualInterestRate() {

return annualInterestRate;

}

public void setAnnualInterestRate(double annualInterestRate) {

this.annualInterestRate = annualInterestRate;

}

public int getNumberOfYears() {

return numberOfYears;

}

public void setNumberOfYears(int numberOfYears) {

this.numberOfYears = numberOfYears;

}

public double getLoanAmount() {

return loanAmount;

}

public void setLoanAmount(double loanAmount) {

this.loanAmount = loanAmount;

}

//Define the method to compute the monthly payment.

public double getMonthlyPayment() {

double monthlyInterestRate = annualInterestRate / 1200;

double monthlyPayment = loanAmount * monthlyInterestRate / (1 -

(Math.pow(1 / (1 + monthlyInterestRate), numberOfYears * 12)));

return monthlyPayment;  

}

//Define the method to get the total payment.

public double getTotalPayment() {

double totalPayment = getMonthlyPayment() * numberOfYears * 12;

return totalPayment;  

}

public java.util.Date getLoanDate() {

return loanDate;

}

}

//Define the client class.

public class ClientLoan extends Application {

 

//Create the server object.

ServerLoan serverLoan;

 

//Declare the variables.

int y;

double r, a, mp=0, tp=0;

String result,d1;

 

//Create the button.

Button b = new Button("Submit");

 

//Define the method stage.

public void start(Stage primaryStage) throws Exception {

 

TimeZone.setDefault(TimeZone.getTimeZone("EST"));

TimeZone.getDefault();

d1 = "Server Started at " +new Date();

 

//Create the GUI.

Label l1=new Label("Annual Interest Rate");

Label l2 = new Label("Number Of Years:");

Label l3 = new Label("Loan Amount");

TextField t1=new TextField();

TextField t2=new TextField();

TextField t3=new TextField();

TextArea ta = new TextArea();

 

//Add the components in the gridpane.

GridPane root = new GridPane();

root.addRow(0, l1, t1);

root.addRow(1, l2, t2, b);

root.addRow(5,l3, t3);

root.addRow(6, ta);

 

//Add gridpane and text area to vbox.

VBox vb = new VBox(root, ta);

 

//Add vbox to the scene.

Scene scene=new Scene(vb,400,250);

 

//Add button click event.

b.setOnAction(value -> {

 

//Get the user input from the text field.

r = Double.parseDouble(t1.getText());

y = Integer.parseInt(t2.getText());

a = Double.parseDouble(t3.getText());

 

//Create the loan class object.

Loan obj = new Loan(r, y, a);

 

//Call the method to compute the results.

mp = obj.getMonthlyPayment();

tp = obj.getTotalPayment();

 

//Format the results.

result = "Annual Interest Rate: "+ r+"\n"+

"Number of Years: "+y+"\n"+

"Loan Amount: "+a+"\n"+

"monthlyPayment: "+mp+"\n"+

"totalPayment: "+tp;

 

//Add the result to the textarea.

ta.setText(result);

 

//Create an object of the server class.

serverLoan = new ServerLoan(this);

});

 

//Set the scene to the stage.

//Set the stage title.

//Make the scene visible.

primaryStage.setScene(scene);

primaryStage.setTitle("ClientLoan");

primaryStage.show();

}

 

//Define the main method lauch the application.

public static void main(String args[])

{  

launch(args);

}

 

//Define the server class.

class ServerLoan extends Stage {

 

//Create the client loan object.

ClientLoan parent;

 

//Create the stage object.

Stage subStage;

 

//Create the text area.

TextArea ta = new TextArea();

 

//Define the constructor.

private ServerLoan(ClientLoan aThis) {

 

//Get the time in desired timezone.

TimeZone.setDefault(TimeZone.getTimeZone("EST"));

TimeZone.getDefault();

 

//Format the date with message.

String d2 = "Connected to client at " +new Date();

 

//Initialize the object.

parent = aThis;

 

//Add the date and the result to

//the text area.

ta.setText(d1);

ta.appendText("\n"+ d2);

ta.appendText("\n"+result);

 

//Create the grouppane.

GridPane root = new GridPane();

 

//Add text area to the group pane.

root.addRow(0, ta);

 

//Initialise the stage object.

subStage = new Stage();

 

//Add gridpane to the scene.

Scene scene = new Scene(root, 400, 200);

 

//Set the scene to the stage.

//Set the stage title.

//Make the scene visible.

subStage.setScene(scene);

subStage.setTitle("ServerLoan");

subStage.show();

}

}

}

Kindly check the Output in the attached image below.

4 0
3 years ago
Read 2 more answers
Assume a program requires the execution of 50 x 106 (50e6) FP instructions, 110 x 106 (110e6) INT instructions, 80 x 106 (80e6)
tresset_1 [31]

Answer:I really don’t know

Explanation:

Um You can look it up though

7 0
3 years ago
Give a big-O estimate for the number additions used in this segment of an algorithm.
rjkz [21]
Big-O notation is a way to describe a function that represents the n amount of times a program/function needs to be executed. 

(I'm assuming that := is a typo and you mean just =, by the way) 

In your case, you have two loops, nested within each other, and both loop to n (inclusive, meaning, that you loop for when i or j is equal to n), and both loops iterate by 1 each loop.

This means that both loops will therefore execute an n amount of times. Now, if the loops were NOT nested, our big-O would be O(2n), because 2 loops would run an n amount of times.

HOWEVER, since the j-loop is nested within i-loop, the j-loop executes every time the i-loop <span>ITERATES. 
</span>
As previously mentioned, for every i-loop, there would be an n amount of executions. So if the i-loop is called an n amount of times by the j loop (which executes n times), the big-O notation would be O(n*n), or O(n^2). 

(tl;dr) In basic, it is O(n^2) because the loops are nested, meaning that the i-loop would be called n times, and for each iteration, it would call the j-loop n times, resulting in n*n runs.

A way to verify this is to write and test program the above. I sometimes find it easier to wrap my head around concepts after testing them myself.
3 0
4 years ago
Other questions:
  • Being able to express your thoughts in an email is a primary technology skill. True or False
    8·2 answers
  • The two types of objects responsible for collecting data are
    14·1 answer
  • Data mining is defined as: a)Separating data and programs such that each can be changed without changing the other b)Allowing ma
    5·1 answer
  • : How does the founder of Wikipedia keep a tight reign on accuracy? HELP PLEZ AT LEAST A PARGRAPH PLES
    6·1 answer
  • All of the following are challenges presented by changing technology as it relates to the special events field EXCEPT: A. the ab
    13·1 answer
  • Why is it difficult to convince top management to commit funds to develop and implement SIS
    5·2 answers
  • What is the first thing you should do when you discover a computer is infected with malware? The second thing?
    7·1 answer
  • Write a statement to declare a variable x with data type int and initialise with the value 10​
    13·1 answer
  • What is data intergrity​
    13·1 answer
  • Discuss new concepts that you have learned about Cisco Devices and how they will be helpful in the workplace.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!