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Anika [276]
3 years ago
12

Write a program that will generate 100 integers between 0 and 1000. Store the even numbers in a sorted linked list called evens.

Store the odd numbers in a different sorted linked list called odds. Print the content of the evens and odds linked lists to the screen. Use the Linked_List class we developed in class.
Computers and Technology
1 answer:
Tomtit [17]3 years ago
8 0

Answer:

see explaination

Explanation:

import random

def num_gen(s, e, n):

r = []

for j in range(n):

r.append(random.randint(s, e))

return r

n = 100

s = 0

e = 1000

l = num_gen(s, e, n)

even_list = []

odd_list = []

for i in l:

if i % 2 == 0:

even_list.append(i)

else:

odd_list.append(i)

print("Even List:", even_list)

print("Odd List:", odd_list)

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Eddi Din [679]

Answer:

Although some devices can be controlled using nothing but their I/O regions, most real devices are a bit more complicated than that. Devices have to deal with the external world, which often includes things such as spinning disks, moving tape, wires to distant places, and so on. Much has to be done in a time frame that is different from, and far slower than, that of the processor. Since it is almost always undesirable to have the processor wait on external events, there must be a way for a device to let the processor know when something has happened.

That way, of course, is interrupts. An interrupt is simply a signal that the hardware can send when it wants the processor's attention. Linux handles interrupts in much the same way that it handles signals in user space. For the most part, a driver need only register a handler for its device's interrupts, and handle them properly when they arrive. Of course, underneath that simple picture there is some complexity; in particular, interrupt handlers are somewhat limited in the actions they can perform as a result of how they are run.

5 0
3 years ago
How do you use loops in code?
Keith_Richards [23]

Answer:

A loop in a computer program is an instruction that repeats until a specified condition is reached. In a loop structure, the loop asks a question. If the answer requires action, it is executed. ... A computer programmer who needs to use the same lines of code many times in a program can use a loop to save time

Explanation:

4 0
3 years ago
Listed three functions tht are ysed in a spreadsheet​
Karo-lina-s [1.5K]

Answer:

The sum function

The count function

The trim function etc.

5 0
2 years ago
LAB: Count characters - methods
tangare [24]

Answer:

i hope understand you

mark me brainlist

Explanation:

using namespace std;

#include <iostream>

 

#include <string.h>

#include <stdlib.h>

#include <stdio.h>

 

#define BLANK_CHAR (' ')

 

 

int CountCharacters(char userChar, char * userString)

{

 

int countReturn=0;

 

int n = strlen(userString);

 

for (int iLoop=0; iLoop<n; iLoop++)

{

       if (userString[iLoop]==userChar)

       {

        countReturn++;

 }

}

return(countReturn);

}

 

/******************************************

    Removes white spaces from passed string; returns pointer

     to the string that is stripped of the whitespace chars;

   

  Returns NULL pointer is empty string is passed;  

     Side Effects:

 CALLER MUST FREE THE OUTPUT BUFFER that is returned

 

 **********************************************************/

char * RemoveSpaces(char * userString)

{

 

 char * outbuff = NULL;

 

 if (userString!=NULL)

 {

   int n = strlen(userString);

    outbuff = (char *) malloc(n);

 

   if (outbuff != NULL)

   {

          memset(outbuff,0,n);

          int iIndex=0;

          //copies non-blank chars to outbuff

         for (int iLoop=0; iLoop<n; iLoop++)

         {

           if (userString[iLoop]!=BLANK_CHAR)

          {

           outbuff[iIndex]=userString[iLoop];

           iIndex++;

   }

   

   } //for

         

   }

   

   }

 return(outbuff);

 

}

 

 

int main()

{

 

 char inbuff[255];

 cout << " PLEASE INPUT THE STRING OF WHICH YOU WOULD LIKE TO STRIP WHITESPACE CHARS :>";

 gets(inbuff);

 

 char * outbuff = RemoveSpaces(inbuff);

 if (outbuff !=NULL)

 {

    cout << ">" << outbuff << "<" << endl;

    free(outbuff);

    }

     

   memset(inbuff,0,255);  

   cout << " PLEASE INPUT THE STRING IN WHICH YOU WOULD LIKE TO SEARCH CHAR :>";

gets(inbuff);

 

  char chChar;

 cout << "PLEASE INPUT THE CHARCTER YOU SEEK :>";

 cin >> chChar;

 

 int iCount = CountCharacters(chChar,inbuff);

 cout << " char " << chChar << " appears " << iCount << " time(s) in >" << inbuff << "<" << endl;

 

}

4 0
3 years ago
for number in range(1,51): if number % 3 == 0 and number % 5 == 0: print('XY') elif number % 5 == 0: print('X') elif number % 3
Elza [17]

Output of the given code is:

Y

X

Y

Y

X

Y

XY

Y

X

Y

Y

X

Y

XY

Y

X

Y

Y

X

Y

XY

Y

X

Explanation:

In the for loop variable "number" will iterate from 1 to 150(inclusive).

in the "if" condition it is checking that the number is divisible by 3 and 5 both if the number is divisible by both 3 & 5 then it will print XY as output.

In the first "elif", if the number is divisible by 5 only then it will print X

as output.And in the last "elif", if number is divisible by 3 only then it will

print Y as output. Nothing will be printed if all three conditions are FALSE.

7 0
4 years ago
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