Answer:
1.0
Explanation:
Priority Tag is to be mentioned in Sitemaps
Various priority values range from 0.1 to 1.0. The highest priority page has the priority value = 1.0, and the lowest priority page has a value of 0.0, and the priority value varies with the priority of the page. And these values are assigned to the priority tag in the sitemap. The sitemap, in fact, is the XML file through which we can set the priority of a webpage.
Answer:
6=110
13=1101
18=10010
27=11011
Explanation:
A decimal number is converted to binary number by constantly dividing the decimal number by 2 till the number becomes zero and then write the remainders in reverse order of obtaining them.Then we will get our binary number.
I will provide you 1 example:-
18/2 = 9 the remainder =0
9/2 = 4 the remainder =1
4/2 = 2 the remainder =0
2/2 = 1 the remainder =0
1/2 = 0 the remainder =1
Writing the remainder in reverse order 10010 hence it is the binary equivalent of 18.
Navigation items are used for moving from one part of the part to a destination using actions and also for passing information. The right option is <em>C. In the navigation menu and the first four items of the </em><em>navigation bar</em><em>, when users are in the app </em>
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There are different methods/ways to implement the Navigation component in a mobile application, we have the following type of Navigation Implementation
- Bottom Navigation
- Drawer Navigation(Slides from Left to right)
- Top Navigation
Learn more about Navigation here:
brainly.com/question/8908486
Step 1: Collection. The first step in the recycling process is always collecting the plastic material that is to be recycled. ...
Step 2: Sorting. ...
Step 3: Washing. ...
Step 4: Resizing. ...
Step 5: Identification and separation of plastics. ...
Step 6: Compounding.
Answer:
Check the explanation
Explanation:
The programmable code to solve the question above will be written in a python programming language <u><em>(which is a high-level, interpreted, general-purpose programming language.)</em></u>
<u><em /></u>
f = open('thisFile.txt', 'r')
w = open('thatFile.txt', 'w')
count = 0
for line in f:
if count % 2 == 0:
w.write(line)
count += 1
w.close()
f.close()
