Answer:
one solution
Step-by-step explanation:
2/3(3y+6)=0
Multiply by 3/2
3/2 *2/3(3y+6)=0*3/2
3y+6 = 0
Subtract 6 from each side
3y = -6
Divide by 3
3y/3 = -6/3
y = -2
There is one solution
Answer:
sure
Step-by-step explanation:
Answer:
For the code we have 3 selections.
The first selection is a digit that must be odd, so the options are {1, 3, 5, 7 ,9}
So we have 5 options.
The second selection is a letter from the set of all the letters (27) minus the set of the vowels (5)
So here we have 27 - 5 = 22 options
The third selection is also a letter from the previous set, but because each letter can be used only one time, and in the previous selection we already selected one of the letters, in this selection we have a letter less than in the previous selection.
Here we have 22 - 1 = 21 options.
The total number of combinations (of possible codes) is equal to the product of the number of options for each selection:
C = 5*22*21 = 2310.
There are 2310 different possible codes
This is a nonlinear equation because there is no common difference between the f(x) values.
The greatest number of groups that can be formed is 10
