1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
riadik2000 [5.3K]
3 years ago
12

The salts you tested were held together by ionic bonds. The compounds were made of two types of ions, positive and negative, tha

t were attracted to each other because of their opposite charges. Some ionic bonds take more energy to break. Based on your investigation, which compounds have bonds that require the most energy to break?
A.
an ionic compound that completely dissolves in water, forming many ions


B.
an ionic compound that partially dissolves in water, forming some ions


C.
an ionic compound that does not dissolve in water, and thus does not form any ions
Chemistry
2 answers:
madam [21]3 years ago
8 0

The plac we go to is e mother tucker

vladimir1956 [14]3 years ago
5 0

Answer:

A an ionic compound that completely dissolves in water, forming many ions

Explanati

You might be interested in
What's the easiest way to find balance in a chemical equation?
ivann1987 [24]
Well not calculus because that has nothing, well mostly nothing to do with balancing chemical equation, so B or C. Now for me personally B is way faster, though C is sometimes faster if you get lucky the way to solve it is B
6 0
2 years ago
Which of these bonds is the weakest?​
Olenka [21]

Answer:

The first one has the weakest bond

Explanation:

The number of atoms together shows how strong the bonds in the second bond it is 4 bonds, the third is 8 bonds, the 4th one is 4 bonds thus why the first bond is the weakest.

6 0
2 years ago
Chromium (Cr) can combine with chlorine (Cl) to form chromium chloride (CrCl3).
lisov135 [29]
2 Cr + 3 Cl2 ------> 2CrCl3
7 0
3 years ago
Two unknown compounds are tested. Compound 1 contains 15.0g of hydrogen and 120.0g of oxygen. Compound 2 contains 2.0g of hydrog
ivann1987 [24]

Answer:

The both compounds are different.

Explanation:

In order to confirm weather both compounds are same we will check the mole ration. If it is same the compounds will be same.

Given data:

For compound 1.

Mass of hydrogen = 15 g

Mass of oxygen = 120 g

Moles of hydrogen and oxygen = ?

Number of moles of hydrogen = 15 g/ 1g/mol = 15 mol

Number of moles of oxygen = 120 g/ 16 g/mol = 7.5 mol

Total number of moles = 22.5 mol

% of hydrogen = 15 /22.5 × 100 = 66.7%

% of oxygen = 7.5 / 22.5× 100 = 33.3%

For compound 2:

Mass of hydrogen = 2 g

Mass of oxygen = 32 g

Moles of hydrogen and oxygen = ?

Number of moles of hydrogen = 2 g/ 1g/mol = 2 mol

Number of moles of oxygen = 32 g/ 16 g/mol = 2 mol

Total number of moles = 4 mol

% of hydrogen = 2 /4 × 100 = 50%

% of oxygen = 2 / 4× 100 = 50%

7 0
2 years ago
Please help me I don't know these.
blagie [28]
Add x on all of them I just took what ur taking rn !!!!!
4 0
2 years ago
Read 2 more answers
Other questions:
  • Which chemical equation is balanced?
    5·2 answers
  • The periodic table tells you how many grams are in a mole of atoms of any
    11·1 answer
  • Suppose you have three monodisperse polymer samples, A, B, and C, with molar masses of 100,000 g/mol, 200,000 g/mol, and 300,000
    7·1 answer
  • Crude oil is a mixture of many liquids. The crude oil enters the bottom of a tall column, where the mixture is heated. The subst
    12·2 answers
  • How many moles are in 1.93x1023 particles of Na3PO4?
    15·2 answers
  • Can vinegar decompose into other harmful chemicals
    6·1 answer
  • Four gases were combined in a gas cylinder with these partial pressures: 3.5 atm N2, 2.8 atm O2, 0.25 atm Ar, and 0.15 atm He. W
    10·1 answer
  • 4. How many grams of ammonium carbonate are needed to decompose in order to produce
    11·1 answer
  • HELP ME PLEASE <br> T-T thanks
    15·1 answer
  • Definition for starch in science ?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!