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kobusy [5.1K]
4 years ago
13

How does plaster efect the strength of wood?

Chemistry
1 answer:
Tatiana [17]4 years ago
7 0
<span>In this work the performance of gypsum plaster and wood particle in pastes and composites was investigated. Wood particles of fineness 0.42 mm and 1.20 mm were employed. Natural wood particles and the treated ones in cold or hot water (80 °C) were performed. The effects of the extractives solutions from the treatments applied to the wood particles on wood-gypsum compatibility were studied. For pastes and composites, water-to-gypsum ratio was 0.65. Wood particles-to-gypsum plaster ratios were 5%, 10% and 15%, in mass. Kinetics of temperature, mechanical performance and dynamic elasticity modulus by ultrasound measurements were applied to evaluate the gypsum plaster pastes and its composites behaviors. Results show that the extractive solutions changed the time of gypsum plaster hydration, being more sensitive to hot water treatment. The composites compressive strength increase with the wood particles pretreatment. The best result was to room temperature treatment. The same performance was found to the modulus of elasticity. Treatments have improved significantly the flexural strength. The best wood particle content was 10%. These results show the possibility of using this wood waste with an easy and simple treatment to make eco-efficient building materials.</span>
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3) How many moles are in 22 grams of argon?
professor190 [17]

Answer:

4) 0.5507 Mol Ar

5) 44.548 Mol AgNO3

6) 2.16107 Mol Li

Explanation:

Divide = grams to mol and mol to molecules

Multiply = molecules to mol and mol to grams.

3) 22 <em>g of Ar</em>           1 mol                   22

-------------------- * ---------------------- = ------------ (turn to decimal) = 0.5507 Mol Ar

                           39.948 <em>g of Ar</em>     39.948

4) AgNO3 = (Ag;  39.948) (N; 14.007) (O^3; 48)  

39.948 + 14.007 + 48 = 101.955

   7.4 x 10^23 Mc    6.02 x 10^23 Mc

  ---------------------- * ------------------------- = 44.548 Mol AgNO3

                                        1 mol        

5)

15g           1 Mol             15

------- * ------------------- = --------- (turn to decimal) = 2.16107 Mol Li

            6.941 g of Li     6.941

7 0
3 years ago
What is metric conversion of:
ArbitrLikvidat [17]

Answer:

The answer is 4 950 mg

Explanation:

5 0
3 years ago
A 3 mL sample of a liquid has a mass of 3 g. What is the density of this liquid?
ad-work [718]
Hey there!

Mass = 3 g

Volume = 3 mL

Density = mass / volume

D = 3 / 3

D = 1,0 g/mL


5 0
3 years ago
Read 2 more answers
Calculate the volume in liters of a potassium iodide solution that contains of potassium iodide . Be sure your answer has the co
Anna11 [10]

Answer:

23.8 L

Explanation:

There is some info missing. I think this is the original question.

<em>Calculate the volume in liters of a 0.0380M potassium iodide solution that contains 150 g of potassium iodide. Be sure your answer has the correct number of significant digits.</em>

<em />

The molar mass of potassium iodide is 166.00 g/mol. The moles corresponding to 150 grams are:

150 g × (1 mol/166.00 g) = 0.904 mol

0.904 moles of potassium iodide are contained in an unknown volume of a 0.0380 mol/L potassium iodide solution. The volume is:

0.904 mol × (1 L/0.0380 mol) = 23.8 L

6 0
3 years ago
You have 8 moles of a gas at 250 K in a 6 L container. What is the pressure of the gas? Show your work
Bogdan [553]

Hello:

In this case, we will use the Clapeyron equation:

P = ?

n = 8 moles

T = 250 K

R = 0.082 atm.L/mol.K

V = 6 L

Therefore:

P * V = n *  R * T

P * 6 = 8 * 0.082* 250

P* 6 = 164

P = 164 / 6

P = 27.33 atm


Hope that helps!

7 0
4 years ago
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