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marysya [2.9K]
3 years ago
10

Help ASAP please!!! Part A and B!!!

Mathematics
1 answer:
ddd [48]3 years ago
4 0
A. Company A.
B. Company C.
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Which expression represents "7 times the sum of 4 and y?" (1 point) 7(4 + y) 7 ⋅ 4 + y 4 + 7 ⋅ y 4(7 + y)
sukhopar [10]

Answer:

7(4 + y)

Step-by-step explanation:

7 0
3 years ago
A battalion of 520 soldiers goes through 16,380 pounds of rations in 3 weeks. If 780 more soldiers join the battalion, how many
Scorpion4ik [409]

They would need 34.125 tons of rations.


In order to find this, we first need to see how many pounds of rations a single soldier eats in a week. To do this, we take the total eaten in 3 weeks and divide by 3. Then we divide by the number of soldiers.


16,380/3 weeks= 5460 lbs per week


5460/520 soldiers = 10.5 lbs per soldier per week


Now we look to see how many soldiers we will have in total after adding. There are 520 to start and we add 780 to get 1300 total. Next we multiply that by the total per soldier per week.


10.5lbs per soldier per week * 1300 soldiers = 13,650lbs per week


Then we have to multiply by the 5 weeks that battalion will be there.


13,650lbs * 5 weeks = 68,250lbs of rations or 24.125 tons.


5 0
4 years ago
A nursery has 10 tree seedlings to give out at 2 workshops. It wants to give out a minimum of 2 seedlings at each workshop. How
11111nata11111 [884]

We are given total 10 tree seedlings.

Number of workshops = 2.

Here order doesn't matters.

<em>When order doesn't matters we apply combination.</em>

We know formula of combination:

C(n,r) = \frac{n!}{r!(n-r)!}

For the given situation, we have

n=10 and r=2.

Plugging values in formula, we get

\frac{10!}{2!(10-8)!}  = \frac{10\times 9\times8!}{2!8!}

\frac{10 \times 9}{2} = \frac{90}{2} =45

<h3>Therefore, 45 different ways can the nursery give out seedlings.</h3>
5 0
3 years ago
a dance team has 80 dancers.The ratio of seventh-grade dancers to all dancers is 5:16.Find the number of seventh-grade dancers o
PSYCHO15rus [73]

Answer:

  25

Step-by-step explanation:

Each of the 16 "ratio units" representing all 80 dancers must stand for ...

  (80 dancers)/(16) = 5 dancers

Then 5 "ratio units" representing seventh-grade dancers will stand for ...

  5 × 5 dancers = 25 dancers

___

Another way to figure this is to write the proportion ...

  (seventh-grade dancers)/(all dancers) = 5/16

  seventh-grade dancers = (all dancers)×(5/16) = 80×5/16

  seventh-grade dancers = 25

5 0
3 years ago
When the expression $-2x^2-20x-53$ is written in the form $a(x+d)^2+e$, where $a$, $d$, and $e$ are constants, then what is the
Sladkaya [172]
We start with 2 x^{2} -20x-53 and wish to write it as a(x+d) ^{2} +e

First, pull 2 out from the first two terms: 2( x^{2} -10x)-53

Let’s look at what is in parenthesis. In the final form this needs to be a perfect square. Right now we have x^{2} -10x and we can obtain -10x by adding -5x and -5x. That is, we can build the following perfect square: x^{2} -10x+25=(x-5) ^{2}

The “problem” with what we just did is that we added to what was given. Let’s put the expression together. We have 2( x-5) ^{2}-53 and when we multiply that out it does not give us what we started with. It gives us 2 x^{2} -20x+50-53=2 x^{2} -20x-3

So you see our expression is not right. It should have a -53 but instead has a -3. So to correct it we need to subtract another 50.

We do this as follows: 2(x-5) ^{2}-53-50 which gives us the final expression we seek:

2(x-5) ^{2}-103

If you multiply this out you will get the exact expression we were given. This means that:
a = 2
d = -5
e =  -103

We are asked for the sum of a, d and e which is 2 + (-5) + (-103) = -106


7 0
3 years ago
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