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lianna [129]
3 years ago
9

Evaulate the definite integral (The s is the integration symbol with indicated values)

Mathematics
1 answer:
Blizzard [7]3 years ago
6 0
\displaystyle\int\limits_{t=1}^{t=4}\frac{t^6-t^2}{t^4}\,\mathrm dt=\int_1^4\left(t^2-\frac1{t^2}\right)\,\mathrm dt=\left(\frac13t^3+\frac1t\right)\bigg|_{t=1}^{t=4}

which evaluates to \dfrac{259}{12}-\dfrac43=\dfrac{81}4.
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