Ask question

Ask question

All categories

3 years ago

15

In practical terms, the mass of an object is closely related to its __________ . A. speed B. volume C. weight

2 answers:

steposvetlana [31]3 years ago

3 0

The best option to go with will be option B.

zalisa [80]3 years ago

3 0

The mass of the object would be B. as mass is how much something takes up not how much something weighs.

If this was the appropriate answer make sure to mark as the brainliest!
-procklown

You might be interested in

I have no clue what to do, please hep

Valentin [98]

Certain games are creative you can learn how to work with a team and accept failure.
step by step explanation:
.

8 0

3 years ago

What temperatures will you find the fourth state of matter?

Charra [1.4K]

Answer:Source The core of plasma ranges in temperature from 11,000° – 14,500° Fahrenheit, thus limiting its applicable uses.

Explanation:

As an ionized gas, plasma's electron density is balanced by positive ions and contains a sufficient amount of electrically charged particles to affect its electrical properties and behavior.

3 0

3 years ago

A city bus travels 6 blocks east and 8 blocks north. Each block is 100 m long. If the bus travels this distance in 15 minutes, w

Eddi Din [679]

Answer:

1.56 m/s

Explanation:

For East direction, the 6 blocks is equivalent to 6*100=600 m

For West direction, 8 blocks is equivalent to 8*100=800 m

Speed is given by s=d/t where s is speed, d is distance covered and t is time taken

Total distance is 600+800=1400m

Time taken is 15 mins, converted to seconds will be 15*60=900 s

Speed, s=1400/900=1.5555555555555 m/s rounded off as 1.56 m/s

4 0

3 years ago

Consider an electron with charge −e and mass m orbiting in a circle around a hydrogen nucleus (a single proton) with charge +e.

alexandr1967 [171]

Answer:

$v=\sqrt{k\frac{e^2}{m_e r}}$ , $2.18\cdot 10^6 m/s$

Explanation:

The magnitude of the electromagnetic force between the electron and the proton in the nucleus is equal to the centripetal force:

$k\frac{(e)(e)}{r^2}=m_e \frac{v^2}{r}$

where

k is the Coulomb constant

e is the magnitude of the charge of the electron

e is the magnitude of the charge of the proton in the nucleus

r is the distance between the electron and the nucleus

v is the speed of the electron

$m_e$ is the mass of the electron

Solving for v, we find

$v=\sqrt{k\frac{e^2}{m_e r}}$

Inside an atom of hydrogen, the distance between the electron and the nucleus is approximately

$r=5.3\cdot 10^{-11}m$

while the electron mass is

$m_e = 9.11\cdot 10^{-31}kg$

and the charge is

$e=1.6\cdot 10^{-19} C$

Substituting into the formula, we find

$v=\sqrt{(9\cdot 10^9 m/s) \frac{(1.6\cdot 10^{-19} C)^2}{(9.11\cdot 10^{-31} kg)(5.3\cdot 10^{-11} m)}}=2.18\cdot 10^6 m/s$

7 0

4 years ago

A particle moving in simple harmonic motion with a period T = 1.5 s passes through the equilibrium point at time t0 = 0 with a v

ch4aika [34]

Answer

given,

Time period= T = 1.5 s

If it's moving through equilibrium point at t₀= 0 with v = 1.0 m/s

v_max=1.00 m/s

we know,

v_ max=A ω

v = A sin (ωt)

-0.50= -1.00 sin (ωt)

sin (ωt) = 0.5

$\omega t = sin^{-1}(0.5)$

$\dfrac{2\pi}{T}\times t =0.524$

$\dfrac{2\pi}{1.5}\times t =0.524$

t = 0.125 s

we have time period T=1.5 it is the time to complete one oscillation

means from eq to right,then left,then eq,then left,then from right to eq

time taken for left = t/4 = 0.125/4 = 0.375 s

smallest value of time

=0.375 + 0.125

= 0.50 sec

7 0

3 years ago