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Vikentia [17]
3 years ago
6

Water is moving at a velocity of 2.00 m/s through a hose with an Internal diameter of 1.60 cm. What is the volume flow rate at t

he nozzle of the hose if it has an Inside dlameter of 6.0 mm?​
Physics
1 answer:
Leya [2.2K]3 years ago
3 0

Answer:

15 m/s

Explanation:

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The previous part could be done without using the decay equation, because the ratio of original 14C14C to present 14C14C was an
salantis [7]

Answer:

The decay constant is 1.21×10^-4/year

Explanation:

Decay constant = 0.693/half-life

Half-life = 5730 years

Decay constant = 0.693/5730 years = 1.21×10^-4/year

4 0
4 years ago
The wavelength of light visible to the human eye is on the order of 5 x 10-7 m. if the speed of light in air is 3 x 108 m/s, fin
juin [17]

The frequency of light wave is 0.6*10^15 Hz.

The relation between the speed of light, frequency, and wavelength is given as

c=λν

Plugging the values in the above equation

3*10^8=5*10^(-7)*ν

ν=0.6*10^15 Hz.

Therefore the frequency of the light wave is 0.6*10^15 Hz.

6 0
4 years ago
What is f if you have an object 2.0 m from the concave mirror, and the image is 4.0 m from the mirror?
dezoksy [38]

Answer:

the f is 1.3 m

Explanation:

Given that

An object 2.0m is from the concave mirror

And, the image is 4.0m from the mirror

We need to find out the f

So,

u = -2 m

v = -4 m

1 ÷ f = 1 ÷ v + 1 ÷ u

= (-1 ÷ 4) + (-1 ÷ 2)

= -3 ÷4

f = -4 ÷ 3

= |1.3| m

Hence, the f is 1.3 m

7 0
3 years ago
The new sweet potato plant grew from the root of the original through
noname [10]
The old sweet potatoes rootlings
3 0
4 years ago
11) Arthur and Betty start walking toward each other when they are 100 m apart. Arthur has a speed of 3.0 m/s and Betty has a sp
sleet_krkn [62]

Answer:

100 m

Explanation:

Arthur and Betty should be walking the same amount of time if they start walking at the same time and stop when they meet = t

Speed of Arthur = 3 m/s

Speed of Betty = 2 m/s

Distance = Speed × time

Distance covered by Arthur = 3t

Distance covered by Betty = 2t

The distance covered by both of them will be 100 m

3t+2t=100\\\Rightarrow 5t=100\\\Rightarrow t=\frac{100}{5}\\\Rightarrow t=20\ s

The speed of dog is 5 m/s

Spot is running back and forth at 5 m/s for 20 seconds

In 20 seconds the distance covered by the dog is

\mathbf{5\times 20}=\mathbf{100\ m}

5 0
4 years ago
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