Ask question

Ask question

All categories

3 years ago

7

If a 5 Kg ball is attached to the end of a string, and it has a velocity of 10 m/s, what is the centripetal acceleration if the

length of the string is 3 ?

1 answer:

Sphinxa [80]3 years ago

5 0

Answer:

probably 5 or mabey I'm not sure don't listen to me ight goodluck,and prayers out to you

You might be interested in

Total distance between Karachi and Hyderabad is 120 km , if a car speed is 40 km/h, In how many hours it can travel back to Hyde

Nuetrik [128]

it takes 6 hours to travel back to Hyderabad

6 0

3 years ago

Read 2 more answers

At summer camp, the swimming course runs the length (L) of a small lake. To determine the length of the course, the camp counsel

sleet_krkn [62]

Answer:

47 m

Explanation:

Data obtained from the question include the following:

Length of dry leg 1 (L1) = 40 m

Length of dry leg 2 (L2) = 25 m

Length of swimming course (L) =..?

The length of the swimming course can be obtained by using pythagoras theory as shown below:

L² = L1² + L2²

L² = 40² + 25²

L² = 1600 + 625

L² = 2225

Take the square root of both side.

L = √2225

L = 47.1 ≈ 47 m

Therefore, the length of the swimming course is approximately 47 m.

7 0

3 years ago

The wavelength of the sound is 0.750m. What is the frequency?

kifflom [539]

wavelength = speed/frequency

==> freq. = speed/wavelength = 342.5/0.75 = 456.67 Hz.

6 0

3 years ago

The angle a vector makes with the x-axis of a coordinate system must be what size in order to make one or more of its components

Aneli [31]

If only 1 option is correct then it is (D)
All the others can also make one component negative, all depends how u measured the angle.
all the best

3 0

3 years ago

Read 2 more answers

An automobile having a mass of 1,000 kg is driven into a brick wall in a safety test. The bumper behaves like a spring with cons

vlada-n [284]

Answer:

$v=2.02\frac{m}{s}$

Explanation:

Assuming no energy lost, according to the law of conservation of energy, the kinetic energy of the automobile becomes potential energy after the crash:

$K=U\\\frac{mv^2}{2}=\frac{kx^2}{2}$

Here m is the automobile's mass, v is the speed of the car before impact, k is the "bumper" constant and x is the compression of the bumper due to the collision. Solving for v:

$v=x\sqrt\frac{k}{m}\\v=2.63*10^{-2}m\sqrt{\frac{5.9*10^6\frac{N}{m}}{10^3kg}}\\v=2.02\frac{m}{s}$

8 0

2 years ago