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ziro4ka [17]
3 years ago
7

If a 5 Kg ball is attached to the end of a string, and it has a velocity of 10 m/s, what is the centripetal acceleration if the

length of the string is 3 ?
Physics
1 answer:
Sphinxa [80]3 years ago
5 0

Answer:

probably 5 or mabey I'm not sure don't listen to me ight goodluck,and prayers out to you

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Which sentence best explains the law of conservation of mass as applied to
drek231 [11]

Answer:

A. The amount of mass changes only slightly during a chemical

reaction.

3 0
2 years ago
When reading a buret, where is the initial and final volumes taken from? The top (where the zero is) or the bottom?. If the bure
liubo4ka [24]
<span>When reading a buret, the initial reading should be taken from the top of the glassware and the final volume should still taken at the top. If the buret is completely, the initial volume for most buret would be zero. though, there are some where their initial starts at 50 decreasing to zero.</span>
5 0
3 years ago
How many digits are in front of the decimal in scientific notation?
nikklg [1K]

Answer:

1

Explanation:

How many digits are in front of the decimal in scientific notation?

7 0
3 years ago
Solve for the length of the inclined plane if the angle equals 19.45 degrees.
mel-nik [20]

The length of the inclined plane is approximately 12 ft

The situation forms a right angle triangle.

<h3>Right triangle</h3>

Right triangle have one of its angle as 90 degrees.

Therefore,

The length of the inclined plane is the hypotenuse of the triangle. The length of the inclined plane can be found using trigonometric ratios.

height = 4 ft

angle(∅) = 19.45°

sin 19.45 = 4 / h

h = 4 / 0.33298412235

h = 12.0125847796

h = 12 ft

Therefore, the length of the inclined plane is approximately 12 ft

learn more on inclined plane:brainly.com/question/14163589?referrer=searchResults

5 0
2 years ago
A rocket on Earth experiences an upward applied force from its thrusters. As a result of this force, the rocket accelerates upwa
gayaneshka [121]

Answer:

F=m(11.8m/s²)

For example, if m=10,000kg, F=118,000N.

Explanation:

There are only two vertical forces acting on the rocket: the force applied from its thrusters F, and its weight mg. So, we can write the equation of motion of the rocket as:

F-mg=ma

Solving for the force F, we obtain that:

F=ma+mg=m(a+g)

Since we know the values for a (2m/s²) and g (9.8m/s²), we have that:

F= m(2m/s^{2}+9.8m/s^{2})\\\\F=m(11.8m/s^{2})

From this relationship, we can calculate some possible values for F and m. For example, if m=10,000kg, we can obtain F:

F=(10,000kg)(11.8m/s^{2})\\\\F=118,000N

In this case, the force from the rocket's thrusters is equal to 118,000N.

5 0
3 years ago
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