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ASHA 777 [7]
2 years ago
15

high contrast toggle How many window coverings are necessary to span 50 windows if each window covering is 15 windows long?

Mathematics
1 answer:
raketka [301]2 years ago
5 0
We know that
<span>If each window covering covers 15 windows, and there are a total of 50 windows to be covered,
it will take -------> 50/15=3.33  windows coverings 
</span>So,
you need more than 3 coverings,
and so take the next whole number --------> 4 window coverings

the answer is
4 window coverings

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The polynomial 6x^2 +37-60 represents an integer. Which expressions represents integer factors of 6x^2+37-60 for all values of x
aniked [119]

Answer:

3x-4 and 2x+15

Step-by-step explanation:

3 0
2 years ago
5(-6-3d)=3(8+7d)(if there is no solution,type in ''no solution'')d= Answer
swat32

In this question, you're solving for d.

Solve for d:

5(-6 - 3d) = 3(8+7d)

Use the distributive property:

-30 - 15d = 3(8+7d)

-30 - 15d = 24 + 21d

Add 30 to both sides:

-15d = 54 + 21d

Subtract 21d from both sides

-36d = 54

Divide both sides by -36

d = -3/2

Answer:

d = -3/2 or -1.5

6 0
2 years ago
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Solve for X.<br> 4(2x + 5) + 2x + 3 = -11
S_A_V [24]
We can begin by rewriting the problem:

4(2x + 5) + 2x + 3 = -11

Let’s solve in steps.

1. Distribute

8x + 20 + 2x + 3 = -11

2. Combine like terms

10x + 23 = -11

3. Subtract 23 from both sides

10x + (23 - 23) = -11 - 23

10x = -34

4. Divide both sides by 10

10 / 10 = 1 (or x)

-34 / 10 = -3.4

Therefore, x = -3.4.
3 0
8 months ago
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ILL put you as brainliest
ICE Princess25 [194]
Just replace x with whatever , and see if it works. If it works then it is a solution; otherwise it's not.

1^2 is not 2
(1/2)^2 isn't 2 either...
and so on
3 0
3 years ago
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Can someone help me with this two column proofs? -this one is confusing to me
Shalnov [3]

Perpendicular bisectors have a particular property: if AB is a perpendicular bisector of CD, then every point lying on AB has the same distance from C and D.

In your case, we have that every point lying on AC has the same distance from B and D.

So, in particular, we have EB=ED, because E lies on AC.

Moreover, since AC is a perpendicular bisector, it is the height of the triangle (if we choose BD as base), and it bisects BD: this means that the triangle is isosceles, so AD=AB.

This means that triangles ABE and ADE have:

  • AD=AB because ABD is isosceles
  • EB=ED because AC is the perpendicular bisector of BD
  • AE in common

So, their sides are all equal, and thus they are congruent.

6 0
3 years ago
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