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3 years ago

5(3 − x) − 4(2 − 3x) > 4

Mathematics

1 answer:

zepelin [54]3 years ago

7 0

Answer:

x > -3/7

Step-by-step explanation:

Eliminate parentheses, collect terms, and subtract the constant on the left.

5(3 -x) -4(2 -3x) > 4

15 -5x -8 +12x > 4

7x +7 > 4

7x > -3

x > -3/7 . . . . . divide by the coefficient of x

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Suppose a triangle has two sides of length 33 amd 37, and that the angle between these two sides is 120°. What is the length of

jeka57 [31]

Answer:

c = 60.65 cm

Step-by-step explanation:

Given that,

The two sides of a triangle are 33 cm and 37 cm.

The angle between these two sides is 120°.

We need to find the length of the third side of the triangle. Let c is the third side. Using cosine rule,

$c^2=a^2+b^2-2ab\cos C$

a = 33 cm, b = 37 cm and C is 120°

So,

$c^2=(33)^2+(37)^2-2\times 33\times 37\cos (120)\\\\c=60.65\ cm$

So, the length of the third side of the triangle is 60.65 cm.

7 0

3 years ago

A bag of nuts weighs 3 ounces and costs 50 cents. What is the unit price? Round to the nearest cent.

galina1969 [7]

Answer:

50 cents/3 ounces = 16.67 cents/ounce

Step-by-step explanation:

maybe

8 0

3 years ago

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In two or three sentences explain how you would solve for the real solutions of the following equation: please help asap!!

g100num [7]

the real solutions for the equation $x^{3}=-64$ are -

$x=4,2+-2\sqrt{3i}$

Step-by-step explanation:

$x^{3}$ = $- 64$

$x^{3} +64$ = 0

We can write 64 as $4^{3}$

$x^{3}$ + $4^{3}$ = 0

using the identity ( $x^{3}+y^{3} = (x+y)(x^{2} -xy+y^{2} )$ )

we get,

= $(x+4) (x^{2} -x*4+4^{2} )$

= $(x+4)(x^{2} -4x+16)$ ....................(1)

solving the quadratic equation ,

$x^{2} -4x+16$ =0

solutions of this quadratic equation can be obtained by

$x=-b +- \sqrt{b^{2}-4ac } /2a$

let use y for factors

$x=-(-4x)+-\sqrt{(-4x^{2} )-4*x^{2} *16} / 2*x^{2}$

$x=4x+-\sqrt{16x^{2} -64x^{2} } /2x^{2}$

$x=4+-\sqrt{16-64}/2$

$x=4+-4\sqrt{3i} /2$

<u /> $x=2+-2\sqrt{3i}$ ..................(2)

from the equation 1 we have,

$x-4=0$

which gives solution $x=4$

and from equation 2 we got $x=2+-2\sqrt{3i}$

so the real solutions for the equation $x^{3}=-64$ are -

$x=4,2+-2\sqrt{3i}$

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2 years ago

Which answer describes the type of sequence?

Stels [109]

Answer:

Neither arithmetic nor geometric.

Step-by-step explanation:

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3 years ago

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What is greater 5.3 or 5.30

Simora [160]

5.30 because 3 is smaller than 30

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3 years ago

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