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egoroff_w [7]
3 years ago
15

Point I is on line segment

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
6 0

Answer:

Step-by-step explanation:

the answer is 14

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There are five envelopes on a table. Four of the envelopes are marked 8, 2, 4 and 1. You are told that the mean of the numbers o
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A polymer is manufactured in a batch chemical process. Viscosity measurements show that it is approximately normally distributed
PilotLPTM [1.2K]

Answer: (751.05, 766.95)

Step-by-step explanation:

We know that the confidence interval for population mean is given by :-

\overline{x}\pm z*\dfrac{\sigma}{\sqrt{n}},

where \sigma =population standard deviation.

\overline{x}= sample mean

n= sample size

z* = Two-tailed critical z-value.

Given :  \sigma= 20

n= 42

\overline{x}=759

We know that from z-table , the two-tailed critical value for 99% confidence interval : z* =2.576

Now, the 99% confidence interval around the true population mean viscosity :-

759\pm (2.5760)\dfrac{20}{\sqrt{42}}\\\\=759\pm (2.5760)(3.086067)\\\\=759\pm7.9497=(759-7.9497,\ 759+7.9497)\]\\=(751.0503,\ 766.9497)\approx(751.05,\ 766.95)

∴ A 99% confidence interval around the true population mean viscosity : (751.05, 766.95)

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4 years ago
Which pair shows equivalent expressions?
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The equivalent expression is A
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