Answer:
3 3/11
Step-by-step explanation:
Answer: 79
Step-by-step explanation:
Given the following :
Graduation Rates:
Grade:82
Weight: 50%
Passing Rates:
Grade: 75
Weight: 30%
Enrollment Numbers:
Grade: 60
Weight: 10%
Career readiness:
Grade: 95
Weight: 10%
Overall score : Σ(grade × weight)
(82 × 50%) + (75 × 30%) + (60 × 10%) + (95 × 10%)
= (41 + 22.5 + 6 + 9.5)
= 79
Hence, overall score is 79
Answer:
Since g(x) = f(2x), this means we substitute 2x in place of x for f(x):
g(x) = f(2x) = (2x)² = 4x²
Graphing this, the parabola is not moved from the parent graph f(x) = x², but the graph is compressed horizontally by a factor of 4.Step-by-step explanation:
Answer:
The number is 91
Step-by-step explanation:
Let x be the ones place digit and y be the tens place digit,
Then the number would be 10y + x,
We have,
y - x = 8
Possible values of y and x = { (8, 0), (9, 1) }
∵ 0 is not the digit of the number,
Hence, y = 9 and x = 1
Therefore, required number = 10(9) + 1 = 90 + 1 = 91
Answer:
the middle 50% of most lengths of pregnancies ranges between 255.62 days and 274.38 days
Step-by-step explanation:
Given that :
Mean = 265
standard deviation = 14
The formula for calculating the z score is 
x = μ + σz
At middle of 50% i.e 0.50
The critical value for 
From standard normal table
+ 0.67 or -0.67
So; when z = -0.67
x = μ + σz
x = 265 + 14(-0.67)
x = 265 -9.38
x = 255.62
when z = +0.67
x = μ + σz
x = 265 + 14 (0.67)
x = 265 + 9.38
x = 274.38
the middle 50% of most lengths of pregnancies ranges between 255.62 days and 274.38 days