Answer:
The coordinates are (-8,7).
Equation of this line is K = -2J + 28
<u>Step-by-step explanation:</u>
Step 1:
The equation can be written in slope intercept form which is y = mx + b
Step 2:
Calculate slope of the line, m = (y2 - y1)/(x2 - x1)
⇒ m = (24 - 20)/(2 - 4) = 4/-2) = -2
Step 3:
Find y-intercept of the line
⇒ b = 28
Step 4:
Substitute values in the equation
⇒ K = -2J + 28
Answer:
y=-5x+1
Step-by-step explanation:
plug the coordinate points to the equation, and find your y intercept
Answer:
-4/5
Step-by-step explanation:
To find the slope of the tangent to the equation at any point we must differentiate the equation.
x^3y+y^2-x^2=5
3x^2y+x^3y'+2yy'-2x=0
Gather terms with y' on one side and terms without on opposing side.
x^3y'+2yy'=2x-3x^2y
Factor left side
y'(x^3+2y)=2x-3x^2y
Divide both sides by (x^3+2y)
y'=(2x-3x^2y)/(x^3+2y)
y' is the slope any tangent to the given equation at point (x,y).
Plug in (2,1):
y'=(2(2)-3(2)^2(1))/((2)^3+2(1))
Simplify:
y'=(4-12)/(8+2)
y'=-8/10
y'=-4/5
Answer:
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