If the product ab is 0, then either a or b must be
1 answer:
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Answer:
Step-by-step explanation:
We have a circle that is split in three sections, two of which we know and we are asked to find the third missing section.
For the circle, we know that 4/5 and 1/10 is fit. Now we need the last one, to solve, we need to get the same denominator and see how much is missing.
Since 1/10 is our highest denominator, let's change 4/5 to have 10 as a denominator. Which would be through multiplying 5 to get 10.
What times 5 equals 10?
2
Now multiply both numerator and denominator by 2 to get our portion.
Now we have the same denominator, let's add our two fractions and see how much we have left.
8/10 + 1/10
9/10
We have 1/10 missing, therefore 1/10 is the answer.
Answer:
See attached
Step-by-step explanation:
Given function:
- y = -2x² + 5x + 8
Table and graph are attached
Zeros are included in the graph
<u>Zero's are obtained:</u>
x = 0 ⇒ y = 8
y = 0 ⇒ Solving quadratic equation
- -2x² + 5x + 8 = 0
- x = (-5 ± √(25 + 2*4*8))/-4
- x = 3.608
- x = -1.108
So zeros are (0, 8), (3.608, 0) and (-1.108, 0)
