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3 years ago

360-357+354-351+...+300-297

Mathematics

2 answers:

ArbitrLikvidat [17]3 years ago

7 0

$360-357+354-351+...+300-297\\\\=(360-357)+(354-351)+...+(300-297)\\\\=\underbrace{3+3+...+3}_{11}=11\times3=33$

Lapatulllka [165]3 years ago

5 0

$x=360-357+354-351+...+300-297=3+3+3+...+3=3n\\\\\ \ \ \ and \ \ \ 300=360-6\cdot(n-1)\ \ \ \Rightarrow\ \ \ 6n=66\ /:6\ \ \ \Rightarrow\ \ \ n=11\\\\x=3\cdot11=33$

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so... firm A got 11,000 invested, turned a profit of 24%, how much is 24% of 11000? well (24/100) * 11000

firm B got 14,000 invested, and returned 15% in profits, how much is 15% of 14000? (15/100) * 14000

part B)

for the amounts above, we get 2640 and 2100 respectively

so, the total profit "amount" is 2640 + 2100 or 4740

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if 25000 is the 100%, how much is 4740 in percentage?

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Step-by-step explanation:

In triangle ABC,

angle CAB = x-3

angle ABC = 4X-3

It is also given that AB=CB

We know that if two sides of any triangle are equal then corresponding sides must also be equal.

Hence

angle ACB = angle CAB

angle ACB = x-3 {Given that angle CAB = x-3 }

We know that sum of all three angles of a triangle is 180 degree so let's add given angles

angle ACB + angle CAB + angle ABC = 180

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6x = 189

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Now plug value of x into

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∠ACB = 28.5

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tatyana61 [14]

Answer:

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