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Svetach [21]
3 years ago
13

Given f(x) = -x + 2, find f(-1)

Mathematics
1 answer:
jarptica [38.1K]3 years ago
3 0

f(x) = -x + 2

f(-1)   This means that they want you to find the value of f(x) or y when x = -1.

f(x) = -x + 2     Substitute/plug in -1 into "x" since x = -1

f(-1) = -(-1) + 2     (two negative signs cancel each other out and become positive)

f(-1) = 1 + 2

f(-1) = 3

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lukranit [14]

Question 21

Let's complete the square

y = 3x^2 + 6x + 5

y-5 = 3x^2 + 6x

y - 5 = 3(x^2 + 2x)

y - 5 = 3(x^2 + 2x + 1 - 1)

y - 5 = 3(x^2+2x+1) - 3

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Answer: Choice D

============================================

Question 22

Through trial and error you should find that choice D is the answer

Basically you plug in each of the given answer choices and see which results in a true statement.

For instance, with choice A we have

y < -4(x+1)^2 - 3

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which is false, so we eliminate choice A

Choice D is the answer because

y < -4(x+1)^2 - 3

-9 < -4(-2+1)^2 - 3

-9 < -7

which is true since -9 is to the left of -7 on the number line.

============================================

Question 25

Answer: Choice B

Explanation:

The quantity (x-4)^2 is always positive regardless of what you pick for x. This is because we are squaring the (x-4). Squaring a negative leads to a positive. Eg: (-4)^2 = 16

Adding on a positive to (x-4)^2 makes the result even more positive. Therefore (x-4)^2 + 1 > 0 is true for any real number x.

Visually this means all solutions of y > (x-4)^2 + 1 reside in quadrants 1 and 2, which are above the x axis.

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3 years ago
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Tresset [83]

Answer:

9.09%

Step-by-step explanation:

You over estimated by 2 feet.  Find out how much 2 feet of 22 is by dividing 2 by 22...

2/22 = 0.090909090909

To convert a decimal to a percent, multiply the decimal by 100%

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3 years ago
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Answer:

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Step-by-step explanation:

<em><u>Given,</u></em>

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<em><u>So,</u></em>

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<em><u>Therefore,</u></em>

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= $(7.80 × 3)

  • <em>[On multiplying]</em>

= $23.40

<em><u>Hence,</u></em>

<em><u>The required cost of 3 cakes is $23.40 (Ans)</u></em>

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