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3 years ago

Given f(x) = -x + 2, find f(-1)

Mathematics

1 answer:

jarptica [38.1K]3 years ago

3 0

f(x) = -x + 2

f(-1) This means that they want you to find the value of f(x) or y when x = -1.

f(x) = -x + 2 Substitute/plug in -1 into "x" since x = -1

f(-1) = -(-1) + 2 (two negative signs cancel each other out and become positive)

f(-1) = 1 + 2

f(-1) = 3

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In a large accounting firm, the proportion of accountants with MBA degrees and at least five years of professional experience is

Rasek [7]

Answer:

The probability that this accountant has an MBA degree or at least five years of professional experience, but not both is 0.3

Step-by-step explanation:

From the given study,

Let A be the event that the accountant has an MBA degree

Let B be the event that the accountant has at least 5 years of professional experience.

P(A) = 0.35

$P(A)^C$ = 1 - P(A)

$P(A)^C$ = 1 - 0.35

$P(A)^C$ = 0.65

$P(B)^C$ = 0.45

P(B) = 1 - $P(B)^C$

P(B) = 1 - 0.45

P(B) = 0.55

P(A ∩ B ) = 0.75 $P(A^C \ \cap \ B^C)$

P(A ∩ B ) = 0.75 [ 1 - P(A ∪ B) ] because $P(A^C \ \cap \ B^C)$ = $P(A \cup B)^C$

SO;

P(A ∩ B ) = 0.75 [ 1 - P(A) - P(B) + P(A ∩ B) ]

P(A ∩ B ) = 0.75 [ 1 - 0.35 - 0.55 + P(A ∩ B) ]

P(A ∩ B ) - 0.75 P(A ∩ B) = 0.75 [1 - 0.35 -0.55 ]

0.25 P(A ∩ B) = 0.075

P(A ∩ B) = $\dfrac{0.075}{0.25}$

P(A ∩ B) = 0.3

The probability that this accountant has an MBA degree or at least five years of professional experience, but not both is: P(A ∪ B ) - P(A ∩ B)

= P(A) + P(B) - 2P( A ∩ B)

= (0.35 + 0.55) - 2(0.3)

= 0.9 - 0.6

= 0.3

∴

The probability that this accountant has an MBA degree or at least five years of professional experience, but not both is 0.3

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3 years ago

Which word best describes what you can observe about the data displayed by a box and whisker plot?

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The answer to this is distribution!! have a good day!!!

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3 years ago

Read 2 more answers

if the eggs in a basket are removed 2 at a time, 1 egg will remain. if the eggs are removed 3 at a time, 2 eggs will remain. if

Yanka [14]

The least number of eggs that could be in the basket is 119.

Multiple of the number:

The multiple is the numbers you get when you multiply a certain number by an integer.

Given,

If the eggs in a basket are removed 2 at a time, 1 egg will remain.

If the eggs are removed 3 at a time, 2 eggs will remain.

If the eggs are removed 4, 5, or 6 at a time, then 3, 4, and 5 eggs will remain, respectfully.

But if they are taken out 7 at a time, no eggs will be left over.

Here we need to find the least number of eggs in the basket.

Let the number of eggs in the basket be N.

We know that,

if the eggs in a basket are removed 2 at a time, one eggs will remain.

So N is 1 less than a multiple of 2, so

=> N=2A-1

If they are removed 3 at a time, 2 eggs remain.

So N is 2 more, and therefore 1 less than, a multiple of 3, so

=> N=3B-1

If the eggs are removed 4...at a time, then 3...eggs remain,

So N is 3 more, and therefore 1 less than, a multiple of 4, so

=> N=4C-1

Similarly,

For 5,

=> N = 5D - 1

For 6,

=> N = 6E - 1

So, if they are taken out 7 at a time, no eggs will be left over.

So,

N => 7F

Where A,B,C,D,E, and F are any positive integer.

Therefore,

N = 2A-1 = 3B-1 = 4C-1 = 5D-1 = 6E-1 = 7F

Add 1 to all those:

N+1 = 2A = 3B = 4C = 5D = 6E = 7F+1

Through this,

N + 1 = 7F + 1

has to be a common multiple of 2,3,4,5,6.

So, the LCM of 2,3,4,5,6 is 60.

So N+1 is a multiple of 60 which means N is 1 less than a multiple of 60.

So we find the least multiple of 60 that is 1 more than a multiple

of 60.

The multiples are, 60, 59, ....but 59 is not a multiple of 7.

The next multiple of 60 is 120.

1 less than 120 is 119, and sure enough, 119 is a multiple of 7.

So,

=> 119 = 17*7.

Therefore, the least number of eggs that could be in the basket is 119.

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1 year ago

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Answer:

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Step-by-step explanation:

Simplify and remove like terms.

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