<h3>
Answer: Bottom left corner (southwest corner)</h3>
The left endpoint is x = 4, but we don't include this endpoint because of the open hole. We use a parenthesis to indicate "don't include the endpoint"
The right endpoint is positive infinity. We always use a parenthesis with either infinity since we cannot reach infinity
The interval from 4 to infinity is written as which is like saying 
Answer:
X = -11
Step-by-step explanation:
-2 (x+3) +5x = -39
3x -6= -39
3x = -33
3x/3 = -33/3
X = -11
4.4 pounds $2.35 = $.53 per pound
10 pound $4.99 = $ .49 per pound
1)
The domain
is every value of x for which f(x) is a real number.
f(x) = 13 / (10-x)
The only x value that would not produce a real number for f(x) is 10, since you
cannot divide a number by zero. Answer is C
2)
F(x)
=(x-6)(x+6)/(x2 - 9)
The vertical asymptotes are x=3 and x=-3. Graph the function on a graphing
calculator to observe the behavior of the function at these points. There is
both a positive and negative vertical asymptote a both x=3 and x=-3. Keep in
mind that the denominator approaches zero at these points, and thus f(x) approaches
either positive or negative infinite, depending on whether the denominator, however small, is a positive or
negative number. Answer is B) 3, -3
3)
F(x) = (x2
+ 4x-7) / (x-7)
Although there is a vertical asymptote as x=7, there is no horizontal asymptote.
This makes sense. As X gets bigger, there is nothing to hold y back from
getting greater and greater. X2 is the dominant term, and it’s only
in the numerator. A) none
4)
(x2 +
8x -2) / (x-2)
This function is very similar in structure to the previous one. Same rules
apply. Dominant term only in the numerator means no horizontal asymptote.
A)None
5)
Our
function approaches 0 as x approaches infinite, and has a vertical asymptote at
x=2 and x=1.
Here’s an easy example: 10 / ((x-2)*(x-1)). At x=2 and x=1, there is both a
positive and negative vertical asymptote. As x approaches infinite, the
numerator is dominated by the denominator, which contains x (actually x2 ),
and thus y approaches zero.
Area of a circle is πr².
Therefore we can get the radius of the great circle (and thus the sphere) by doing √(A / <span>π).
</span>
√(28.6 / <span>π) = 3.017 to 3DP.
</span>
Surface area of a sphere is 4πr².
4<span>π(3.017)</span>² = 114.4 to 1DP
