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Sedaia [141]
3 years ago
14

Solve the system of equations.

Mathematics
2 answers:
tino4ka555 [31]3 years ago
5 0

<u>Answer:</u>

(2, 7) or (-6, 1)

<u>Step-by-step explanation:</u>

We are given two equations:

y=x+5; and

y = x^2+5x-7

Since y is the subject for both the equations so we can put the values of y equal to each other to get:

x+5=x^2+5x-7

x^2+5x-x-7-5=0

x^2+4x-12=0

Factorizing the expression to get:

x^2-2x+6x-12=0

x(x-2)+6(x-2)=0

(x-2) (x+6) = 0

x=2, x= -6

Putting x = 2 and x = -6 in any of the equations to get the values of y:

y=x+5

y =2+5

y=7

and

y =(-6)+5

y=1

Therefore, solution to these equation is (2, 7) or (-6, 1).

Setler79 [48]3 years ago
5 0

Alina is correct, give her the brainliest! :)

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Answer:

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Step-by-step explanation:

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They want a 90% confidence interval.  Our sample size is 7, so since n < 30, we will use a t-score.  Look up the value under the 10% area in 2 tails column, and degree of freedom is 6 (degree of freedom is always 1 less than sample size for confidence intervals when n < 30)

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We rounded down to the nearest person in the interval because we don't want to over estimate.  It said 28.55, so more than 28 but not quite 29, so if we use 29 as the lower limit, we could over estimate.  It's better to use 28 and underestimate a little when considering customer flow.

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3 years ago
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Answer:

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Step-by-step explanation:

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Apply radical rule \sf \sqrt{a \cdot b}=\sqrt{a}\sqrt{b}

\sf \implies \dfrac{3-\sqrt{16}\sqrt{2}}{1+\sqrt{2} }

As \sf \sqrt{16}=4:

\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} }

Multiply by the conjugate:

\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} } \times \dfrac{1-\sqrt{2} }{1-\sqrt{2} }

\sf \implies \dfrac{(3-4\sqrt{2})(1-\sqrt{2})}{(1+\sqrt{2})(1-\sqrt{2})}

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2 years ago
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Step-by-step explanation:

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