Can you google that?, i also need that answer
Hi
perimeter of rectangle is : 2 length+2 width .
to progress in math, you must practice.
So , I let you do the first one which is the esaiest.
48 ) V147+ V147 + V108+V108 = 2V147 +2V108 = 2 ( V147+V108)
Answer:
JML=142 degrees
Step-by-step explanation:
This shape is a rhombus, as all 4 sides are equal, but the angle measures are not. One of the properties of a rhombus is that opposite angles are congruent, and adjacent angles are supplementary. Only the second one is important. Since angles KLM and angle JML are supplementary, the equation KLM+JML=180 can be used. KLM is then substituted by the given angle measure, 38 degrees, to get an equation such as JML+38=180. Now, to solve for JML, 38 must be subtracted from both sides of the equation, which leaves teh answer of JML=142.
Determine the defined range k=0
move expression to the left side and change its sign so it would be the problem = 0
write all numerators above the least common denominator 6k (*2*)-Squared
calculate the sum or the difference
check the solution in the defined range
hope this helped you
