Help! Don’t understand any of this!!

grigory [225]

In question 1, both of your answers are correct, but I don't understand the process you went through in the 'a' part.

R = v/I . That's a correct formula.
But it doesn't help you in this form, because you need to find I
So turn it into a helpful form ... Solve it for I, so it says I=something.

R= v/I

Multiply each side by I : R I = V.

Now divide each side by R: I= V/R .
THERE'S the equation you want.

I = V / R

I = 1.5 / 10 = 0.15 Amp.

That's slightly cleaner, although I don't really understand what you were actually thinking in that part.

But again ... You answered both parts correctly, and your process in b is fine.

6 0

3 years ago

What is the equation for density (feel free to use go*ogle search, my parents blocked it on my computer so I can't look it up my

12345 [234]

Answer: The answer is right here and it is corrct

:) $\rho ={\frac {m}{V}}$

Explanation: I think you can unblocked it but Hope this help :)

6 0

3 years ago

Read 2 more answers

Two blocks connected by a light string are being pulled across a frictionless horizontal tabletop by a hanging 16.2-N weight (bl

Artemon [7]

Newton's second law allows us to find the results for the string tensions are:

T₁ = 6.7 N

T₂ = 16.54 N

Newton's second law gives a relationship between force, mass and acceleration of bodies

∑ F = ma

Where the bold letters indicate vectors, F is the force, m the mass and the acceleration.

Free-body diagrams are representations of the forces applied to bodies without the details of them.

The reference system is a coordinate system with respect to which the forces decompose, in this case the x-axis is parallel to the plane and the positive direction in the direction of movement, the y-axis is perpendicular to the plane.

In the attachment we see a free-body diagram of the three-block system.

Let's apply Newton's second law to each body.

Block C

Y-axis

$W_c -T_2 = m_c a$

Block A

X axis

$T_2 - T_1 - W_a_x = m_a a$

Y axis

$N_a - W_a_y = 0$

Block B

X axis

$T_1 - W_b_x = m_b a$

Y axis

$N_b - W_b_y =0$

Let's use trigonometry to find the components of the weight.

Block A

cos θ = $\frac{W_a_y}{W_a}$

sin θ = $\frac{W_a_x}{W_a}$

$W_a_y = W_a cos \theta$

$W_a_x= W_a sin \theta$

Block B

cos θ = $\frac{W_b_y}{W_b}$

sin θ = $\frac{W_b_x}{W_b}$

$W_b_y = W_b cos \theta \\W_b_x = W_b sin \theta$

Let's write our system of equations.

$W_c - T_2 = m_c a \\ T_2 - T_1 - W_a_x = m_a a \\T_1 - W_b_x = m_b a$

Let's find the acceleration of the bodies, adding the equations.

$W_c - W_a_x - W_b_x = ( m_a+m_b+m_c) a\\$

The weight is

W = mg

Let's substitute

$(m_c - m_a -m_b ) g \ sin \theta = ( m_c+m_a+m_b) \ a \\a= \frac{ m_c-m_a-m_b }{ m_a+m_b+m_c} \ g sin \theta$

Indicate ma mass of the block a ma = 1.00 kg, the mass of the block b mb = 2.2 kg and the weight of the block c Wc = 16.2 N, let's find the mass of block c.

m_c = Wc / g

m_c = 16.2 / 9.8

m_c = 1.65 kg

we substitute the values

$a= \frac{1.65 -2.20 -1.00}{1.65+2.20+1.00} \ 9.8 \ sin \theta \\a= -0.3096 sin \theta$

The negative sign indicates that the system is descending, to be able to give a specified value an angle is needed, they assume that the angle of the ramp is 45º

a = - 0.3196 sin 45

a = -0.226 m / s

Taking the acceleration we are going to look for the tensions.

From the equation of block C

$W_c - T_2 = m_c a \\T_2 = m_c ( g-a)\\T_2 = 1.65 ( 9.8 + 0.226)$

T₂ = 16.54 N

From the equation of block B

$T_1 - W_b_x = m_b a\\T_1 = m_b (a + g sin \theta)\\T_1 = 1.00 (-0.226 + 9.8 \ sin 45)$

T₁ = 6.7 N

In conclusion using Newton's second law we can find the results for the string tensions are:

T₁ = 6.7 N

T₂ = 16.54 N

Learn more here: brainly.com/question/20575355

7 0

2 years ago

Destiny is eating lunch at her favorite cafe when her friend Jada calls and says she wants to meet her. Jada is calling from a c

NeTakaya

Answer:

Explanation:

Let time taken by Jada in driving be t hour .

distance travelled by jada = 55 t

a )

Time of drive by destiny = t - 10 min

= t - .167 hour

distance of travel by destiny = 70 ( t - .167 )

Total distance = 45 miles

55 t + 70 ( t - .167 ) = 45

55t + 70 t - 11.69 = 45

125 t = 56.69

t = .453 hour = 27.21 minutes

b )

distance travelled by Destiny = 70 ( t - .167 )

70 ( .453 - .167 )

= 20.02 miles .

5 0

3 years ago

g A point source of light is submerged 2.5 m below the surface of a lake and emits rays in all directions. On the surface of the

andreyandreev [35.5K]

Answer:

$r= 2.5 m tan(48.61) = 2.84m$

Explanation:

For this case the situation is explained in the figure attached.

We can find the maximum radius r with the angle of incidence or critical angle (xi). If we have that the angle is higher than the light we will see a reflecting property. We can assume that the refracted angle for this case is 90 and if we use the following trigonometric property we have:

$tan (x_i) = \frac{r}{d}$