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2 years ago

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In preparation for the final exam, our astronomy study group has reconvened to discuss Mercury's unique orbital properties. They

have expressed the following ideas: Student A: When Mercury revolves around the Sun 4 times, it rotates around its axis 6 times. Student B: When Mercury revolves around the Sun 6 times, it rotates around its axis 10 times. Student C: When Mercury revolves around the Sun 8 times, it rotates around its axis 12 times. Which student is incorrect

1 answer:

grigory [225]2 years ago

6 0

Answer:

The only incorrect statement is from student B

Explanation:

The planet mercury has a period of revolution of 58.7 Earth days and a rotation period around the sun of 87 days 23 ha, approximately 88 Earth days.

Let's examine student claims using these rotation periods

Student A. The time for 4 turns around the sun is

t = 4 88

t = 352 / 58.7 Earth days

In this time I make as many rotations on itself each one with a time to = 58.7 Earth days

#_rotaciones = t / to

#_rotations = 352 / 58.7

#_rotations = 6

therefore this statement is TRUE

student B. the planet rotates 6 times around the Sun

t = 6 88

t = 528 s

The number of rotations on itself is

#_rotaciones = t / to

#_rotations = 528 / 58.7

#_rotations = 9

False, turn 9 times

Student C. 8 turns around the sun

t = 8 88

t = 704 days

the number of turns on itself is

#_rotaciones = t / to

#_rotations = 704 / 58.7

#_rotations = 12

True

The only incorrect statement is from student B

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Answer:

A. elements of the same kind with different numbers of neutrons

Explanation:

As we know that an atom is represented by

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here we know that

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Answer:

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Explanation:

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1. Una bola de 0.510 kg de masa se mueve al este (dirección +x) con una rapidez de 4.80 m/s y choca frontalmente con una bola de

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Responder:

3,37 m / s, + ve x - dirección

Explicación:

Utilizando la ley de conservación de la cantidad de movimiento expresada por la fórmula;

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m1 y m2 son las masas de los objetos

u1 y u2 son sus velocidades iniciales

v es su velocidad común

Dado

m1 = 0,519 kg

u1 = 4,80 m / s

m2 = 0,220 kg

u2 = 0 m / s (cuerpo en reposo)

Necesario

Velocidad común v

Sustituir en la fórmula los valores dados;

0,519 (4,8) + 0,22 (0) = (0,519 + 0,220) v

2,4912 + 0 = 0,739 v

2,4912 = 0,739v

Dividir ambos lados por 0,739

2,4912 / 0,739 = 0,739 / 0,739

<em>v = 3,37 m / s </em>

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disa [49]

Answer with Explanation:

We are given that

$F=-8\hat{i}+6\hat{j}$

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We know that

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By using the formula

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Substitute the values then we get

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