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Sonbull [250]
2 years ago
14

In preparation for the final exam, our astronomy study group has reconvened to discuss Mercury's unique orbital properties. They

have expressed the following ideas: Student A: When Mercury revolves around the Sun 4 times, it rotates around its axis 6 times. Student B: When Mercury revolves around the Sun 6 times, it rotates around its axis 10 times. Student C: When Mercury revolves around the Sun 8 times, it rotates around its axis 12 times. Which student is incorrect
Physics
1 answer:
grigory [225]2 years ago
6 0

Answer:

The only incorrect statement is from student B

Explanation:

The planet mercury has a period of revolution of 58.7 Earth days and a rotation period around the sun of 87 days 23 ha, approximately 88 Earth days.

Let's examine student claims using these rotation periods

Student A. The time for 4 turns around the sun is

           t = 4 88

           t = 352 / 58.7 Earth days

In this time I make as many rotations on itself each one with a time to = 58.7 Earth days

           #_rotaciones = t / to

           #_rotations = 352 / 58.7

           #_rotations = 6

therefore this statement is TRUE

student B. the planet rotates 6 times around the Sun

          t = 6 88

          t = 528 s

The number of rotations on itself is

           #_rotaciones = t / to

           #_rotations = 528 / 58.7

           #_rotations = 9

False, turn 9 times

Student C. 8 turns around the sun

           t = 8 88

           t = 704 days

the number of turns on itself is

            #_rotaciones = t / to

            #_rotations = 704 / 58.7

            #_rotations = 12

True

The only incorrect statement is from student B

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