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emmainna [20.7K]
3 years ago
9

Based electromagnetic spectrum? on its surface temperature of 6,000 K, most photons that leave the Sun's surface lie in which re

gion of the________
A) microwave
B) infrared
C) visible
D) ultraviolet
E) X-ray
Physics
1 answer:
masha68 [24]3 years ago
7 0

Answer:

option C

Explanation:

given,

Temperature of the surface = 6000 K

using formula to calculate \lambda_{max}

\lambda_{max} = \dfrac{0.0029\ K.m}{T}

\lambda_{max} is the maximum wavelength emission in meter.

T is the temperature in kelvin.

\lambda_{max} = \dfrac{0.0029}{6000}

\lambda_{max} = \dfrac{0.0029}{6000}

\lambda_{max} = 4.8333 \times 10^{-7}

\lambda_{max} = 4833\ A^0

the wavelength is in Visible range

The Correct answer is option C

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3 years ago
How much work must be done to bring three electrons from a great distance apart to 3.0×10−10 m from one another (at the corners
Natasha_Volkova [10]

Answer:

Potential\ Energy=Work \ Done=2.301*10^{-18} J

Work  done to bring three electrons from a great distance apart to 3.0×10−10 m from one another (at the corners of an equilateral triangle) is 2.301*10^{-18} Joules

Explanation:

The potential energy is given by:

U=Q*V

where:

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Potential Difference=V=\frac{kq}{r}

So,

Potential\ Energy=\frac{Qkq}{r} \\Q=q\\Potential\ Energy=\frac{kq^2}{r}

Where:

k is Coulomb Constant=8.99*10^9 Nm^2/C^2

q is the charge on electron=-1.6*10^-19 C

r is the distance=3.0*10^{-10}m

For 3 Electrons Potential Energy or work Done is:

Potential\ Energy=3*\frac{kq^2}{r}

Potential\ Energy=3*\frac{(8.99*10^9)(-1.6*10^{-19})^2}{3*10^{-10}}\\Potential\ Energy=2.301*10^{-18} J

Work  done to bring three electrons from a great distance apart to 3.0×10−10 m from one another (at the corners of an equilateral triangle) is 2.301*10^{-18} Joules

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3 years ago
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Katyanochek1 [597]

Answer:

increases

Explanation:

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Explanation:

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