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MA_775_DIABLO [31]
2 years ago
13

What would the acceleration of a car be from a stoplight if it started at 0 m/s and reached a

Physics
1 answer:
trapecia [35]2 years ago
3 0

Answer:

The acceleration of a car would be:  a=12.8 m/s²

Explanation:

Given

Initial velocity = v_1=0 m/s

Final velocity = v_f=100 m/s

Time elapsed = t = 7.8 s

To determine

We need to determine the acceleration of a car.

We know that acceleration is basically the rate of change in velocity over time.

Thus,

We can determine the acceleration using the formula

\:\:\:a=\:\frac{v_f-v_i}{t}

where

  • a is the acceleration
  • v_1 is the initial velocity
  • v_f is the final velocity
  • t is time elapsed

now substituting the values v_1=0,  v_f=100, and t = 7.8 in the formula

\:\:\:a=\:\frac{v_f-v_i}{t}

a=\:\frac{100-0}{7.8}

a=\frac{100}{7.8}

a=12.8 m/s²

Therefore, the acceleration of a car would be:  a=12.8 m/s²

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Answer:

8) 709.8875 J

9) The object is at 7.24375 m from the ground

10) Kinetic energy increases as the object falls.

Explanation:

We use the expression for the displacement h(t) as a function of time of an object experiencing free fall:

h(t) = hi - (g/2) t^2

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h(0.75) = 10 - 4/9 (0.75)^2 = 7.24375 m

This is the position of the 10 kg object after 0.75 seconds (answer for part 9)

Knowing this position we can calculate the potential energy of the object when it is at this height, using the formula:

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3 years ago
3 points
Ilia_Sergeevich [38]

Answer:

Potential

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The water in the bathtub has more potential energy than that in the tea cup because it has a greater number of water molecules.

Mass is a parameter that is very instrumental in determining potential energy.

The potential energy of a body is the energy due to the position of that body.

   Potential energy  = mass x acceleration due gravity x height

Mass is the amount of matter in a substance. Water in the tub will have more mass and contain a greater number of water molecules there in.

Since potential energy is directly proportional to mass, then, it will have a greater amount of potential energy.

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2 years ago
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To solve this problem we will apply the expression of charge per unit of time in a capacitor with a given resistance. Mathematically said expression is given as

q(t) = e^{-\frac{t}{(R*C)}}

Here,

q = Charge

t = Time

R = Resistance

C = Capacitance

When the charge reach its half value it has passed 10ms, then the equation is,

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RC = 0.014s

We know that RC is equal to the time constant, then

T = RC  = 0.014s = 14ms

Therefore the time constant for the process is about 14ms

5 0
3 years ago
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