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UNO [17]
3 years ago
10

1.) True or False. Scientists have drilled through the crust to reach the mantle.

Physics
2 answers:
Eva8 [605]3 years ago
4 0

Answer:

False

Explanation:

We have never made it to the mantle.

Nonamiya [84]3 years ago
3 0
False. That is the correct answer
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The length of the side of a cube having a density of 12.6 g/ml and a mass of 7.65 g is __________ cm.
qaws [65]

Density is the characteristic property of a substance.  It is the measure of mass of the substance divided by its volume (density= mass/volume). Manipulate the given formula to come up with the formula for the volume. Therefore, volume is equals to mass of a substance divided by its density (Vol= mass/density). Given 12.6 g/ml as density and 7.65 g mass, volume is equals to 0.60714 ml, since 1 ml = 1cm^3, volume is equals to 0.60714 cm^3 then extract the cube root of the volume to get the length of the cube in cm which is equal to 0.84677 cm.




4 0
4 years ago
From t=0 onwards what happens to the voltage across the inductor annd the curreent through the inductor relative to their values
gregori [183]

From t=0 onwards I changes slowly and V changes abruptly across the inductor.

At time t=0, the voltage across the inductor equalises the battery voltage; nevertheless, Lenz's Law states that this induced EMF will always be opposed to the polarity of the battery. The voltage across the inductor is equivalent to the voltage of a battery because the inductor at time zero behaves like a second battery of the same voltage linked in reverse.

Because current can never be zero, voltage across the inductor decreases with time. If it did, there would be no back EMF to stop the current from flowing through the inductor because the magnetic field would not be changing. As a result, the inductor will become less of an open circuit as the current increases over time. The inductor will essentially behave like a resistor.

Learn more about inductor here:

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3 0
2 years ago
Which best explains satellites? the moon is a satellite of the earth, and the earth is a satellite of the sun. mercury and pluto
Basile [38]
<span>the moon is a satellite of the earth, and the earth is a satellite of the sun.
that is the best answer</span>
6 0
3 years ago
Read 2 more answers
A periodic wave travels from one medium to another. Which pair of variables are likely to change in the process?Select one of th
anyanavicka [17]
<h3><u>Answer;</u></h3>

A. velocity and wavelength

<h3><u>Explanation;</u></h3>
  • <em><u>When a wave travels from one medium to another it undergoes refraction which results to the change in direction. </u></em>
  • <u><em>Refraction of a wave is one of the property of waves that occurs when a wave changes direction when it passes from one medium to another. </em></u>This occurs as a result of bending of the wave which occurs since the mediums involved are of different density and refractive index.
  • <em><u>Apart from the change in direction, refraction is accompanied by the change in wavelength of a wave and thus a change in speed.</u></em>
7 0
4 years ago
Read 2 more answers
Light bulbs are typically rated by their power dissipation when operated at a given voltage.
stira [4]

(b) At 24 W and 12 V, the bulbs can operate with the largest current of 2 A.

Answer:

Option B.

Explanation:

Power consumed in light bulbs are measured in terms of voltage and current. As it is known that power dissipated in an electric circuit is directly proportional to the square of current and also to resistance.

Power = I²R

As by Ohm's law, V = IR, then Power = VI

Here, V is the voltage and I is the current flowing through the bulb.

So here the power and voltage is given and we have to determine the largest current. So from the formula it can stated that current flowing through the bulb will be directly proportional to the power dissipated by the circuit and inversely proportional to the voltage at which the circuit is operated.

So for the given options, the current value is as follows:

(a) I = P/V = 3.2/6=0.5333 A

(b) I = P/V = 24/12 = 2 A

(c) I= P/V = 16/18 =0.9 A

(d) I = P/V = 32/24 = 1.3 A

Thus, the option B is having the maximum voltage at which the bulb can be operated. So at 24 W and 12 V, the bulbs can operate with the largest current of 2 A.

7 0
3 years ago
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