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3 years ago

1.) True or False. Scientists have drilled through the crust to reach the mantle.

Physics

2 answers:

Eva8 [605]3 years ago

4 0

Answer:

False

Explanation:

We have never made it to the mantle.

Nonamiya [84]3 years ago

3 0

False. That is the correct answer

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An electron moving along the x axis has an initial speed of 1 × 106 m/s at the origin. Its speed is reduced to 5 × 105 m/s at th

mina [271]

Answer:

-2.13 V

Explanation:

Given parameters are:

$v_i = 1 * 10^6$ m/s

$v_f = 5 * 10^5$ m/s

$q = -e = 1.602 * 10^{-19}$ C

$m = 9.109 * 10^{-31}$ kg

By conservation of energy principle, we know that the potential difference between two points is equal to the change in the kinetic energy between these points.

$-\Delta U = \Delta KE\\\\-e\Delta V = \frac{1}{2} mv_f^2 - \frac{1}{2} mv_i^2$

Hence,

$1.602*10^{-19}\Delta V = \frac{1}{2}*9.11*10^{-31}((5*10^5)^2 - (1*10^6)^2)$

⇒ $\Delta V = -2.13$ V

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4 years ago

Wan and Nurul sat on a see-saw. The see-saw is imbalanced because Wan’s mass is 45 kg while Nurul’s mass is only 30 kg. Suggest

Alex Ar [27]

We have that the see-saw will be balance if a weight of $x=15kg$ is added to Nural's side of the see-saw

$x=15kg$

From the Question we are told that

Wan’s mass is $M_w=45 kg$

Nurul’s mass is $M_n= 30 kg.$

Generally

The Will be balance when the weight on both sides of the see-saw are equal

$M_w=M_n+x$

$45=30+x$

$x=45-30$

$x=15kg$

In conclusion

The see-saw will be balance if a weight of $x=15kg$ is added to Nural's side of the see-saw

$x=15kg$

For more information on this visit

brainly.com/question/22255610

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3 years ago

Which step follows the identification of the problem in the technological design process?

STALIN [3.7K]

The answer is research.

5 0

3 years ago

You arrive in my class 45 seconds after leaving math which is 85 meters away. How fast did you travel?

levacccp [35]

Speed = 85/45
units m/s

7 0

3 years ago

A 10-kg disk-shaped flywheel of radius 9.0 cm rotates with a rotational speed of 320 rad/s. Part A Determine the rotational mome

Leya [2.2K]

Answer:

(A). The rotational momentum of the flywheel is 12.96 kg m²/s.

(B). The rotational speed of sphere is 400 rad/s.

Explanation:

Given that,

Mass of disk = 10 kg

Radius = 9.0 cm

Rotational speed = 320 m/s

(A). We need to calculate the rotational momentum of the flywheel.

Using formula of momentum

$L=I\omega$

$L=\dfrac{1}{2}mr^2\omega$

Put the value into the formula

$L=\dfrac{1}{2}\times10\times(9.0\times10^{-2})^2\times320$

$L=12.96\ kg m^2/s$

(B). Rotation momentum of sphere is same rotational momentum of the flywheel

We need to calculate the magnitude of the rotational speed of sphere

Using formula of rotational momentum

$L_{sphere}=L_{flywheel}$

$I\omega_{sphere}=I\omega_{flywheel}$

$\omega_{sphere}=\dfrac{I\omega_{flywheel}}{I_{sphere}}$

$\omega_{sphere}=\dfrac{I\omega_{flywheel}}{\dfrac{2}{5}mr^2}$

Put the value into the formula

$\omega_{sphere}=\dfrac{12.96}{\dfrac{2}{5}\times10\times(9.0\times10^{-2})^2}$

$\omega_{sphere}=400\ rad/s$

Hence, (A). The rotational momentum of the flywheel is 12.96 kg m²/s.

(B). The rotational speed of sphere is 400 rad/s.

4 0

3 years ago