Using conditional probability, it is found that there is a 0.1 = 10% probability that the chosen coin was the fair coin.
Conditional Probability
In which
- P(B|A) is the probability of event B happening, given that A happened.
- is the probability of both A and B happening.
- P(A) is the probability of A happening.
In this problem:
- Event A: Three heads.
- Event B: Fair coin.
The probability associated with 3 heads are:
- out of 0.5(fair coin).
- 1 out of 0.5(biased).
Hence:
The probability of 3 heads and the fair coin is:
Then, the conditional probability is:
0.1 = 10% probability that the chosen coin was the fair coin.
A similar problem is given at brainly.com/question/14398287
It is 015 & with a line and a book o crove hdgsgub
Answer:
critical value = 1.645
The 90% confidence interval = ( -22.62, -17.58)
Step-by-step explanation:
Given that:
the sample size = 178
the sample size = 226
the sample mean = 54.4
the sample mean = 74.5
population standard deviation = 18.58
population standard deviation = 9.52
level of significance ∝ = 1 - 0.90 = 0.10
The critical value for is 1.645
For the construction of our confidence interval, we use 90% since that is used to find the critical value.
∴
The margin of error =
2.52
The lower limit =
= ( 54.4-74.5) - (2.52)
= -20.1 - 2.52
= -22.62
The upper limit =
= ( 54.4-74.5) + (2.52)
= -20.1 + 2.52
= -17.58
The 90% confidence interval = ( -22.62, -17.58)
Answer:
500
Step-by-step explanation: