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3 years ago

Consider the enlargement of the pentagon

Mathematics

1 answer:

Katena32 [7]3 years ago

3 0

Answer:

b. 3.3 centimeters

Step-by-step explanation:

$\frac{7}{x} =\frac{15}{7} \\\\15x = 49\\x=3.3$

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Can -111/-80 be simplified? If so, what can it be simplified to and how?

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Step-by-step explanation:

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3 years ago

Mary gets a $15 allowance each week. She also earns extra money by washing cars. She earns $5 for every car she washes. Each wee

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3 years ago

Using GCF write an expression that is equivalent to 16p+48

aalyn [17]

You start by looking at what number can divide evenly into both 16 and 48. Both numbers are divisible by 16. 16 goes into 16 once and 16 goes into 48 three times. So you divide each term by 16 and your expression should look like this: 16 (p+3)

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3 years ago

Find the volume of the prism. Round to the nearest tenth if necessary.

Lubov Fominskaja [6]

Answer:

14.7 (Because you asked for no units)

Step-by-step explanation:

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2 years ago

Explain why f(x) = x^2+4x+3/x^2-x-2 is not continuous at x = -1.

liberstina [14]

Answer:

The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)

Step-by-step explanation:

We have the following expression

$f(x) = \frac{x^2+4x+3}{x^2-x-2}$

Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.

Now we search that values of x make 0 the denominator factoring the polynomial $x^2-x-2$

We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.

These numbers are -2 and 1

Then the factors are:

$(x-2) (x + 1)$

We do the same with the numerator

$x^2+4x+3$

We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.

These numbers are 3 and 1

Then the factors are:

$(x+3)(x + 1)$

Therefore

$f(x) = \frac{(x+3)(x+1)}{(x-2)(x+1)}$

Note that $\frac{(x+1)}{(x+1)}=1$ only if $x \neq -1$

So since $x = -1$ is not included in the domain the function has a discontinuity in $x = -1$

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3 years ago