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dolphi86 [110]
3 years ago
9

x}^{3} + 3 {}^{x} = 17" alt=" {x}^{3} + 3 {}^{x} = 17" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
dimaraw [331]3 years ago
3 0

Answer:

X = 2

Step-by-step explanation:

if \: {x}^{3}  +  {3}^{x}  = 17 \: we \: can \: conclude \: that \: x \: is \: equal \: to \: two \\  {2}^{3}  +  {3}^{2}  = 8 + 9 = 17

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A friend claims that it will rain today with probability 30% and tomorrow with probability four times as great as today. Which o
alexgriva [62]

Answer:

The claim cannot be true because any probability is between 0 and 1

Step-by-step explanation:

Probability is a concept used to mathematically provide a measure or determine the possibility that an event will occur. However, due to the nature of upcoming events, it is almost impossible to predict some events with absolute certainty, therefore, the chance of an event can be predicted based on the likelihood of the event occurring with probability values ranging from 0 to 1 or 0% to 100%. Where a value of 0 or 0% shows that it is certain that the event will not occur, while 1 or 100% indicates that it absolutely certain that an event will occur.

6 0
2 years ago
What kind of transformation is this?
neonofarm [45]

Answer:

Reflection

Step-by-step explanation:

It is a reflection because it is like they are looking in the mirror.

3 0
2 years ago
Read 2 more answers
3+2/3(3-x)<-7 please help I am stuck
asambeis [7]
Solve the problem then state if it's true or false- this is an order of operation problem. 3+2/3(3-X) this is the problem. Now distribute, 3+ 2/3(3)- 2/3(x)= 3+2- 2/3x so the final expression would be 5-2/3x I don't know about the <-7 part but that's the solution to the first one
8 0
3 years ago
Trigonometry pile up. Anyone mind helping me out with this one?
S_A_V [24]
cos34^o=\frac{8}{a};\ cos34^o\approx0.829\\\\\frac{8}{a}=0.829\to a\approx9.65\\\\9.65-2.5+3.6=10.75\\\\cos11^o=\frac{b}{10.75};\ cos11^o\approx0.981\\\\\frac{b}{10.75}=0.981\to b\approx10.55\\\\10.55-2.1+2.9=11.35\\\\c^2+3.8^2=11.35^2\\\\c^2=11.35^2-3.8^2\\\\c\approx10.69

10.69-3.2=7.49\\\\tan42^o=\frac{d}{7.49};\ tan42^o\approx0.9\\\\\frac{d}{7.49}=0.9\to d\approx6.74\\\\sin37^o=\frac{6.74}{e};\ sin37^o\approx0.602\\\\\frac{6.74}{e}=0.602\to e\approx11.2\\\\11.2+4.3=15.5\\\\sin53^o=\frac{f}{15.5};\ sin53^o\approx0.8\\\\\frac{f}{15.5}=0.8\to f\approx12.4

12.4-2.2=10.2\\\\g^2=10.2^2+1.7^2\to g\approx10.34\\\\cos21^o=\frac{10.34}{h};\ cos21^o\approx0.934\\\\\frac{10.34}{h}=0.934\to h=11.07\\\\11.07+1.7=12.77\\\\sin71^o=\frac{x}{12.77};\ sin71^o\approx0.946\\\\\frac{x}{12.77}=0.946\to x\approx12.1\ (cm)\leftarrow Answer

4 0
3 years ago
I need help right now this due today(you have been in this situation).
Free_Kalibri [48]

Answer:

7.62

Step-by-step explanation:

We can draw another point at (-3, -4) named C to get a right-angled triangle.

AC = 2 (by counting)

BC = 7 (by counting)

Using Pythagoras Theorem,

AC^{2} +BC^{2} =AB^{2}

2^2+7^2=AB^2

4+49=AB^2

AB^2=58

AB=\sqrt{58} = 7.62 (nearest hundredth)

8 0
3 years ago
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