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dolphi86 [110]

2 years ago

x}^{3} + 3 {}^{x} = 17" alt=" {x}^{3} + 3 {}^{x} = 17" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

dimaraw [331]2 years ago

3 0

Answer:

X = 2

Step-by-step explanation:

$if \: {x}^{3} + {3}^{x} = 17 \: we \: can \: conclude \: that \: x \: is \: equal \: to \: two \\ {2}^{3} + {3}^{2} = 8 + 9 = 17$

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Find the base of an isosceles triangle whose area is 60 cm² and the length of one of its equal sides is 13 cm.

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Answer:

Base = 24 cm or 10cm

Step-by-step explanation:

REMEMBER:
An isosceles triangle ABC with base BC = ‘b' & height AD = ‘h' & its equal sides =13 cm & area = 60 cm²

Using the formulas

$A=\frac{bh_b}{2}$

$h_b=\sqrt{a^2-\frac{b^2}{4} }$

There are 2 solutions for $b$

$b=2\sqrt{2} \frac{A}{\sqrt{a^2+\sqrt{a^4-4A^2} } } =2*\sqrt{2} *\frac{60}{\sqrt{13^2+\sqrt{13^4-4*60^2} } }$ ≈ $10cm$ $b=2\sqrt{2} \frac{A}{\sqrt{a^2+\sqrt{a^4-4A^2} } } =2*\sqrt{2} *\frac{60}{\sqrt{13^2-\sqrt{13^4-4*60^2} } }=24cm$

Less complex:

Area of a triangle = 1/2 * b * h = 60

=> h = 120/b

In right triangle ABD

13² = h² + b² /4 ( by Pythagoras law)

=>169 = 120²/b² + b²/4

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=> b^4 - 676 b² + 57600 = 0

=> b² = 676 +- √(676² - 4*57600) / 2

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=> b² = 1152/2 , 200 /2

=> b² = 576 , 100

=> b = 24, 10

So, Base = 24 cm or 10cm

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