Answer:
3
Explanation:
mass number minus the atomic number
35-32
3
d=? v=2.5 u=0 and t=5 therefore the formula to be used to find the distance my brother covered is d=1/2(v-u)t
d=1/2(2.5-0)5
=6.15m
Answer:
Explanation:
See the file attached .
b ) Range of projectile
= u²sin2θ / g
= 42² sin32 x 2 / g
= 42² sin64 / 9.8
= 161.8 m
c )
Max height = u² sin²32 / 2 g
= 42² sin²32 / 2x 9.8
= 25.27 m .
Answer:
The time spent by the rock in air is 3 s.
Explanation:
Given;
initial horizontal velocity of the rock, u = 20 m/s
horizontal distance traveled by rock, R = 60 m
The the range of the projectile is given by;
R = vt
where;
v is the initial horizontal velocity of the rock
t is the time spent by the rock in air
t = R/v
t = 60 / 20
t = 3 s
Therefore, the time spent by the rock in air is 3 s.
It will decrease in the same proportion.