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Serjik [45]
3 years ago
7

A 1.5 kilogram car is moving at 10 meters per second east. A braking force acts on the car for 5.0 seconds, reducing its velocit

y to 2.0 meters second east.
Determine the impulse experienced by the car.
Physics
1 answer:
Arada [10]3 years ago
8 0

Answer:

I don't know

Explanation:

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Natalija [7]

Answer:

I think it's c but don't know for sure

3 0
2 years ago
Why do fishermen like fishing during a full moon?
Anna35 [415]

Answer:

The full moon attracts more fish towards the surface of the water.

Explanation:

It is a proven fact that fish are attracted to shiny/glowing items. for example, a metal fishing lure. Or, an angler fish light-bulb.

5 0
3 years ago
A ball is thrown at 25 m/s at an angle of 55 degrees.
yuradex [85]

Answer:65 seconds

Explanation:just had the quiz

4 0
3 years ago
-2
photoshop1234 [79]

Answer:-2

Explanation:

7 0
2 years ago
When an object is placed 110 cm from a diverging thin lens, its image is found to be 55 cm from the lens. The lens is removed, a
Kazeer [188]

Explanation:

Given that,

Object distance u= -110 cm

Image distance v= 55 cm

We need to calculate the focal length for diverging lens

Using formula of lens

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

Put the value into the formula

\dfrac{1}{-f}=\dfrac{1}{55}-\dfrac{1}{-110}

\dfrac{1}{f}=-\dfrac{3}{110}

f=-36.6\ cm

The focal length of the diverging lens is 36.6 cm.

Now given a thin lens with same magnitude of focal length 36.6 cm is replaced.    

Here, The object distance is again the same.

We need to calculate the image distance for converging lens

Using formula of lens

\dfrac{1}{36.6}=\dfrac{1}{v}-\dfrac{1}{-110}

Here, focal length is positive for converging lens

\dfrac{1}{v}=\dfrac{1}{36.6}-\dfrac{1}{110}

\dfrac{1}{v}=\dfrac{367}{20130}

v=54.85\ cm

The distance of the image is 54.85 cm from converging lens.

Hence, This is the required solution.

5 0
3 years ago
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