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Serjik [45]
3 years ago
7

A 1.5 kilogram car is moving at 10 meters per second east. A braking force acts on the car for 5.0 seconds, reducing its velocit

y to 2.0 meters second east.
Determine the impulse experienced by the car.
Physics
1 answer:
Arada [10]3 years ago
8 0

Answer:

I don't know

Explanation:

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An object with a mass of 3.0kg has a force of 9.0 newtons applied to it. What is the resulting acceleration of
Sindrei [870]

Answer:

The acceleration is: a=3 \frac{m}{s^2}

Explanation:

To answer this, we need to recall Newton's Second Law of motion, that states that an object of mass m would accelerate (change its state of uniform motion) proportional to the force (F) that is applied , and exemplified by the following equation:

F=m\,a

From here, and using the given values for mass (m = 3 kg) and force (F = 9 N), we can derive the value of the acceleration as shown below (notice that since all quantities are given in SI units, the resulting acceleration will also be in Si units (\frac{m}{s^2}):

F=m\,a\\9\,N=3\,kg\,a\\a=\frac{9}{3} \frac{m}{s^2} \\a=3 \frac{m}{s^2}

3 0
4 years ago
A small uniform disk and a small uniform sphere are released simultaneously at the top of a high inclined plane, and they roll d
Yuri [45]

Answer:

the sphere

Explanation:

From the given information,

A free flow body diagrammatic expression  for the small uniform disk and a small uniform sphere which are released simultaneously at the top of a high inclined plane  can be seen in the image attached below.

From the diagram;

The Normal force mgsinθ - Friction force F  = mass m × acceleration a

Meanwhile; the frictional force

F = \dfrac{I \alpha }{R}

where

\alpha = \dfrac{a}{R}  in a rolling motion

Then;

F = \dfrac{I a }{R^2}

∴

The Normal force mgsinθ - F  =  m ×  a     can be re-written as:

\mathtt{mg sin \ \theta- \dfrac{Ia}{R^2} = ma}

making a the subject of the formula, we have:

a = (\dfrac{mg \ sin \theta}{m + \dfrac{I}{R^2}})

Similarly;

I = mk²  in which k is the radius of gyration

∴

replacing I = mk² into the above equation , we have:

a = (\dfrac{mg \ sin \theta}{m + \dfrac{mk^2}{R^2}})

where;

the uniform disk \dfrac{k^2}{R^2 }= \dfrac{1}{2}  

the uniform  sphere \dfrac{k^2}{R^2 }= \dfrac{2}{5}

∴

a = \dfrac{2}{3} \ g sin \theta \ for \ the \ uniform \ disk

a = \dfrac{5}{7} \ g sin \theta \ for \ the \ uniform \ sphere

We can now see that the uniform sphere is greater than the disk as such the sphere will reach the bottom first.

4 0
3 years ago
When a cyclist is decelerating uphill the forces on him are balanced or unbalanced ​
olga_2 [115]

Answer:

Unbalanced

Explanation:

A cyclist decelerating uphill has unbalanced forces acting on him. An unbalanced force acting on a body has a net force which is greater than zero. When a body is accelerating or decelerating, the forces are not balanced.

  • A body with a net force of zero has balanced forces acting on it.
  • Such body is moving with constant acceleration.
  • According to newton's first law of motion" a body will remain in state of rest or of uniform motion unless an external force acts on it".
  • The external force causes acceleration to change drastically.
7 0
3 years ago
What type of interaction occurs when a wave hits an object that it cannot pass?
alexandr402 [8]
It makes an echo and it circles around it.
5 0
3 years ago
What is matter? I WILL MARK YOU THE BRAINLIEST!
UNO [17]

Answer:

Liquid, gas, and solid

Explanation:

4 0
3 years ago
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