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Serjik [45]
3 years ago
7

A 1.5 kilogram car is moving at 10 meters per second east. A braking force acts on the car for 5.0 seconds, reducing its velocit

y to 2.0 meters second east.
Determine the impulse experienced by the car.
Physics
1 answer:
Arada [10]3 years ago
8 0

Answer:

I don't know

Explanation:

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Which perspective is most directly involved with the study of how brain
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Answer:

biopsychlogy

Explanation:https://www.answers.com/Q/Which_perspective_is_most_directly_involved_with_the_study_of_how_brain_development_might_affect_behavior

6 0
4 years ago
Gold in its pure form is too soft to be used for most jewelry. Therefore, the gold is mixed with other metals to produce an allo
Novay_Z [31]

Answer:

Explanation:18kt alloy contains

i) 75% of gold

rhogold=19.3g/cm^3

=75/100×19.3

=14.475g/cm^3

ii) 16% of silver

rhosilver=10.5g/cm^3

=16/100×10.5

=1.68g/cm^3

iii) 9% of copper

rhocopper =8.90g/cm^3

=9/100×8.9

=0.801g/cm^3

Overall density of 18kt gold

=(0.801+1.68+14.475)g/cm^3

=16.956g/cm^3

=17g/cm^3 to 3s.f

6 0
3 years ago
A locomotive engine pulls a train with a constant force comment on whether its acceleration will increase or decrease if more co
julia-pushkina [17]

Explanation:

the acceleration will be unchanged according to newton second law of motion

7 0
3 years ago
A pitcher throws a 0.140 kg baseball, and it approaches the bat at a speed of 35.0 m/s. The bat does Wnc = 75.0 J of work on the
Eva8 [605]

Answer:

The speed of the ball is 42.5 m/s

Explanation:

The initial kinetic energy of the ball is:

K_1=\frac{1}{2} m v_0^2=\frac{1}{2}*0.140 kg*(35.0 m/s)^2= 85.75 J

The speed of the ball after leaving the bat is:

K_2=K_1+W_{nc}\\ \frac{1}{2}mV^2= 85.75 J + 75 J\\ (\frac{1}{2}mV^2)2=( 160.75 J)2\\ mV^2= 321.5 J\\ V^2= \frac{321.5 J}{0.140kg} \\ V=\sqrt{\frac{321.5 J}{0.140kg}}

V=47.92 m/s

Using kinematic equation we can find the speed of the ball after being 25 m above the point of collision:

V_f^2-V^2=-2gh

V_f^2-(47.92 m/s)^2=-2*9.81m/s^2*25m

V_f^2=-2*9.81m/s^2*25m+(47.92 m/s)^2

V_f=\sqrt{-2*9.81m/s^2*25m+(47.92 m/s)^2}

V_f=42.5m/s

3 0
3 years ago
A is a non-contact breaking of the basketball rules <br>​
ElenaW [278]
A foul occurs when a player or coach breaks a rule covering either contact with an opposing player of unsportsmanlike action. Basketball is a so-called non-contact sport but basketball rules recognize that is not really possible to have 10 players running around a small area without making some contact.
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3 years ago
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