The way their suppose to do it
If the answer is not C D then is A bc of the way it crosses over
Answer:
3.6 × 10⁵ N/C = 360 kN/C
Explanation:
Let R = 2.0 cm be the radius of the sphere and q = -8.0 nC be the charge in it. Let q₁ be the charge at radius r = 1.0 cm. Since the charge is uniformly distributed, the volume charge density is constant. So, q/4πR³ = q₁/4πr³
q₁ = q(r/R)³. The electric field due to q₁ at r is E₁ = kq₁/r² = kq(r/R)³/r² = kqr/R³
The electric field due to the point charge q₂ = 5.0 nC is E₂ = kq₂/r².
So, the magnitude of the total electric field at r = 1.0 cm is
E = E₁ + E₂ = kqr/R³ + kq₂/r² = k(qr/R³ + q₂/r²)
E = 9 × 10⁹(-8 × 10⁻⁹ C × 1 × 10⁻² m/(2 × 10⁻² m)³ + 5 × 10⁻⁹ C/(1 × 10⁻² m)²)
E = 9 × 10⁹(-1 × 10⁻⁵ + 5 × 10⁻⁵)
E = 9 × 10⁹(4 × 10⁻⁵)
E = 36 × 10⁴ N/C = 3.6 × 10⁵ N/C = 360 kN/C
Answer: k = 2π / λ
Explanation: Wavenumber k (propagation number) is a measure of spatial scale. Wavenumber can be defined as the number of wavelengths per unit distance and can be expressed in terms of lambda λ, wavelength.
This definition can be mathematically expressed as
k = 2π / λ, where k is wavenumber and λ is wavelength
Answer:
NICE HANDWRITING. I've done this before and I'm sure everything is correct. Although I would re-check to see if you had any mistakes with your calculations. Good job!
Explanation:
