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4 years ago

13

Divers in acapulco, mexico, dive headfirst at 8 feet per second from the top of a cliff 87 feet above the pacific ocean. during

which time period will the diver's height exceed that of the cliff?

1 answer:

xxMikexx [17]4 years ago

8 0

Depends on the wieght of his genitals.

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A 0.58 kg mass is moving horizontally with a speed of 6.0 m/s when it strikes a vertical wall. The mass rebounds with a speed of

Sunny_sXe [5.5K]

Answer:

$5.8\; {\rm kg\cdot m \cdot s^{-1}}$ .

Explanation:

If the mass of an object is $m$ and the velocity of that object is $v$ , the linear momentum of that object would be $m\, v$ .

Assume that the initial velocity of the mass is positive ( $6.0\; {\rm m\cdot s^{-1}}$ .) However, the direction of the velocity is reversed after the impact. Thus, the sign of the new velocity of the object would be negative- the opposite of that of the initial velocity. The new velocity would be $(-4.0\; {\rm m\cdot s^{-1}})$ .

Thus, the change in the velocity of the mass would be:

$\begin{aligned}& (\text{Change in Velocity}) \\ =\; & (\text{Final Velocity}) - (\text{Initial Velocity}) \\ =\; & (-4.0\; {\rm m\cdot s^{-1}}) - (6.0\; {\rm m\cdot s^{-1}}) \\ =\; & (-10\; {\rm m\cdot s^{-1})\end{aligned}$ .

The change in the linear momentum of the mass would be:

$\begin{aligned} & \text{change in momentum} \\ =\; & (\text{mass}) \times (\text{change in velocity}) \\ =\; & 0.58\; {\rm kg} \times (-10\; {\rm m\cdot s^{-1}}) \\ =\; & (-5.8\; {\rm kg \cdot m \cdot s^{-1}})\end{aligned}$ .

Thus, the magnitude of the change of the linear momentum would be $5.8\; {\rm kg \cdot m \cdot s^{-1}}$ .

7 0

3 years ago

Egg A is dropped from a height of 1m onto the floor. Egg B is dropped from a height of 1m into a bucket of water. Which statemen

NeTakaya

Answer:

maybe it's because a bucket of water has more density than egg B

3 0

3 years ago

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a student standing between two walls shouts once.he hears the first echo after 3 seconds and the next after 5 seconds. calculate

Karolina [17]

Explanation:

It took $t_1 =1.5\:\text{s}$ for the sound to reach the 1st wall and at the same time time, the same sound took $t_2 = 2.5\:\text{s}$ to reach the 2nd wall. Assuming that the sound travels at 343 m/s, then let $x_1$ be the distance of the person to the 1st wall and $x_2$ be the distance to the 2nd wall. So the distance between the walls X is

$X = x_1 + x_2 = v_st_1 + v_st_2 = v_s(t_1 + t_2)$

$\:\:\:\:\:= (343\:\text{m/s})(4.0\:\text{s}) = 1372\:\text{m}$

6 0

3 years ago

Which of the following has a positive charge and a mass of one?

Dmitrij [34]

Answer:

the answer is protons b

Explanation:

brainliest if 1st one..

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3 years ago

What is the name of the force that keeps the planets and other celestial bodies orbiting around the sun

zhenek [66]

Gravity is the name of the force that keeps the planets in orbit

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3 years ago

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