Answer:
(3x^2 + 2)(x + 4).
Step-by-step explanation:
3x3 + 12x2 + 2x + 8
3x^2(x + 4) + 2(x + 4) The x + 4 is common to the 2 groups so we have:
(3x^2 + 2)(x + 4).
No, a cubic equation can not have three complex roots. This is because it turns twice and one end goes to positive infinity and one end goes to negative infinity. Thus, one of these MUST cross the x-axis at some point, meaning y = 0 and a real root exists.
Yes, a cubic equation can have three real roots if it cuts the x-axis three times.
Answer:
its the top right answer choice
you'd simply just need to subtract 80 from 210 since its 10 per visit, and after 8 visits well its self explanatory
Step-by-step explanation:
its the top right answer choice
you'd simply just need to subtract 80 from 210 since its 10 per visit, and after 8 visits well its self explanatory
So every 1 out of 10 students is checked also is there anymore to this question?
