Problem 1
With limits, you are looking to see what happens when x gets closer to some value. For example, as x gets closer to x = 2 (from the left and right side), then y is getting closer and closer to y = 1/2. Therefore the limiting value is 1/2
Another example: as x gets closer to x = 4 from the right hand side, the y value gets closer to y = 4. This y value is different if you approach x = 0 from the left side (y would approach y = 1/2)
Use examples like this and you'll get the results you see in "figure 1"
For any function values, you'll look for actual points on the graph. A point does not exist if there is an open circle. There is an open circle at x = 2 for instance, so that's why f(2) = UND. On the other hand, f(0) is defined and it is equal to 4 as the point (0,4) is on the function curve.
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Problem 2
This is basically an extension of problem 1. The same idea applies. See "figure 2" (in the attached images) for the answers.
Reason:
2. SD ⊥ HT. ∴ ∠SDH = ∠SDT =90°
3. Given (It is given in the question)
5. RHS congruence
(Here, the right angle, hypotenuse and one side of ΔSHD is congruent to that of ΔSTD).
Statement:
4. Line segment SD = SD
(Reflexive property is used to prove congruence of triangles. This property is used when an angle or line segment is congruent to itself.)
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Answer:
The fourth angle = 60°
Step-by-step explanation:
the sum of the interior angles of a quadrilateral is 360°.
The fourth angle = 360° - 100° - 120° - 80° = 60°