Problem
Solution
For this case we know that the vertex is given by (3,6) and the genera equation for a parabola is given by:
y= a(x-h)^2 +k
Where h = 3, k=6 and replacing we have:
y= a(x-3)^2 +6
And we can find the value of a with the point given x= 4, y=4
4= a(4-3)^2 +6
4= a +6
a= 4-6=-2
And the correct equation would be:
d. y= -2(x-3)^2 +6
Given:
Point = (8, 4)
To find:
The slope-intercept form of the equation of the line.
Solution:
Slope of this line = .
Slope of the line is same as the slope of .
Slope of the line (m) =
General form of line:
y = mx + b
---------- (1)
It contains the point (8, 4). Substitute x = 8 and y = 4 in (1).
Subtract 4 from both sides, we get
b = 0
Substitute b = 0 in (1).
Equation of the line:
<u>Complete the sentence:</u>
; I used the general form of a line in slope-intercept form, y = mx + b. The slope, m is
. Then I substituted 8 for x and 4 for y into the standard form and solved for b, which is 0.
The top of the escalator exists 9 feet far from the ground floor.
<h3>How to estimate how far is the top of the escalator from the ground floor? </h3>
Let h denote the distance between the top of the escalator from the ground floor.
We have existed given that the angle of depression from the top of the escalator to the floor stands 36.84°, and the escalator exists 15 feet long.
The side h exists opposite side and 15 feet side exists hypotenuse of a right triangle.
8.993737 = h
Therefore, the top of the escalator exists 9 feet far from the ground floor.
To learn more about the sides of a triangle refer to:
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