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Andrej [43]
4 years ago
7

The angle between 0 and 2π in radians that is coterminal with the angle 41/6π in radians is?

Mathematics
1 answer:
Inessa05 [86]4 years ago
3 0

Answer:

  5π/6

Step-by-step explanation:

Subtract multiples of 2π until you find the angle in the desired range.

  41π/6 -36π/6 = 5π/6

The angle 5π/6 is co-terminal with 41π/6.

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Rewrite in simplest form. 5x3 + 5x2 - 3x - 3x2
vovangra [49]

Answer:

(25)-(3)

Step-by-step explanation:

7 0
3 years ago
Plz plz help me on number 6 plz plz help
tigry1 [53]
The answer would actually be A because if you make 3 1/4 a mixed number you would get 13/4 which equals 3.25. Now divide 3.25 by 4 because you will dividing these pizzas to 4 people. This gives me 0.8125. Then I would multiply 1/4 to 3.3125 which gives me 0.203125 and when you make this to an improper fraction it will come out to be 13/64 which is choice A. I hope this helps you! I am also sorry for what happened yesterday. 
3 0
3 years ago
Squareroot(y-1) + 3 = y
jek_recluse [69]
Note:xy means x times y and x(y) means the same thing

so
first we get rid of square root then
make the equation equal to zero becaues if
xy=0 then x or/and y=0



squareroot(y-1)+3=y

isolate the squareroot
subtrac 3 from boht sides

squareroot(y-1)=y-3

square both sides (since they are equal, you should be able to square both sides and still make it true)

(squareroot(y-1))^2=(y-3)^2
(y-1)=(y-3)(y-3)
y-1=y^2-6y+9
subtrac y from both sides
-1=y^2-7y+9
add 1 to both sides
0=y^2-7y+10
find what two number multiply to make 10 and add to get -7
the answer is -2 and -5

0=(y-5)(y-2)
therfore
y-5=0
and/or
y-2=0

therefor
y=5 or/and 2 might work
let's try out 2
square root(2-1)+3=2
square root(1)+3=2
1+3=2
false
so 2 doesn't work



let's try 5
squareroot(5-1)+3=5
squareroot(4)+3=5
2+3=5
5=5
true

y=5
7 0
3 years ago
Erin has a bag of jelly beans and skittles. She has 4 types of jelly beans (red, yellow, green, blue) and 2 types of skittles (g
tatiyna

Answer:

I don't know I'm really sorry please don't be angry

and if you want my social media cause your angry I'll give

3 0
3 years ago
I need help on how to do combinations
Veronika [31]
Ok sure! Let's start with the marbles first. We have one red one blue and one green. There is a red and a blue cube. All we do is list the possible combinations of one marble and one cube. The answer would be : 1 blue marble, 1 blue cube. 1 red marble, 1 blue cube. 1 green marble, 1 blue cube. Then again but with the red cube. So in all, there are 6 possible combinations. Hope this helps. ☺️
3 0
3 years ago
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