The value of x in the congruent triangles abc and dec is 1
<h3>How to determine the value x?</h3>
The question implies that the triangles abc and dec are congruent triangles.
The congruent sides are:
ab = de
bc = ce = 4
ac = cd = 5
The congruent side ab = de implies that:
4x - 1 = x + 2
Collect like terms
4x - x = 2 + 1
Evaluate the like terms
3x = 3
Divide through by 3
x = 1
Hence, the value of x is 1
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<u>Complete question</u>
Two triangles, abc and cde, share a common vertex c on a grid. in triangle abc, side ab is 4x - 1, side bc is 4, side ac is 5. in triangle cde, side cd is 5, side de is x + 2, side ce is 4. If Δabc ≅ Δdec, what is the value of x? a. x = 8 b. x = 5 c. x = 4 d. x = 1 e. x = 2
200-(25•2)=150
150-(22•3)=84
84-25=59
Andrew has $59 left
The expression which is equivalent to the given expression as in the task content is; 1.5 raised to the fifteenth power divided by 0.7 raised to the twelfth power.
<h3>What is the expression which is equivalent to the given expression?</h3>
According to the task content, it follows that the expression given is;
(1.5⁵/0.7⁴)³
= 1.5^(3×5) /0.7^(4×3)
= 1.5¹⁵/0.7¹².
Hence, the expression which is equivalent is; 1.5 raised to the fifteenth power divided by 0.7 raised to the twelfth power.
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