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Arturiano [62]
3 years ago
11

How could you Katie? I thought you were taking this relationship seriously.. :c

Chemistry
1 answer:
mestny [16]3 years ago
4 0
It happens bro, don’t fret too much on it. You’ll find someone better
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6. What volume will 9.38g of the mineral quartz (silicon dioxide SiO2)
Tcecarenko [31]

Answer:

The answer is

<h2>3.54 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}  \\

From the question

mass = 9.38 g

density = 2.65 g/cm³

The volume of the quartz is

volume =  \frac{9.38}{2.65}  \\  = 3.539622641...

We have the final answer as

<h3>3.54 mL</h3>

Hope this helps you

7 0
4 years ago
4.65 L of nitrogen at standard pressure is compressed into a 0.480 L container. What is the new pressure in kPa?
Semenov [28]
Assuming that nitrogen gas is ideal, we can use the equation PV = nRT to relate first conditions to the second condition. At constant temperature, pressure and volume are indirectly related as follows:

P = k / V

k is equal nRT

P1V1 = P2V2
P2 = 101.325 ( 4.65 ) / .480 = 981.586 kPa
6 0
4 years ago
Which letter pattern best represents seafloor spreading? (Hint: Letter "f" represents the mid-
labwork [276]

Answer:

anna ou

Explanation:

6 0
3 years ago
Read 2 more answers
The rate constants of some reactions double with every 10 degree rise in temperature. Assume that a reaction takes place at 271
AfilCa [17]

Answer : The activation energy for the reaction is, 119.7 J

Explanation :

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

or,

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = rate constant at 271 K

K_2 = rate constant at 281 K = 2K_1

Ea = activation energy for the reaction = ?

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 271 K

T_2 = final temperature = 281 K

Now put all the given values in this formula, we get:

\log (\frac{2K_1}{K_1})=\frac{Ea}{2.303\times 8.314J/mole.K}[\frac{1}{271K}-\frac{1}{281K}]

Ea=119.7J

Therefore, the activation energy for the reaction is, 119.7 J

3 0
4 years ago
Help me answer this question for points!
labwork [276]

Answer:

I am pretty sure Danny Duncan told me 69

Explanation:

niice

6 0
3 years ago
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