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3 years ago

How could you Katie? I thought you were taking this relationship seriously.. :c

Chemistry

1 answer:

mestny [16]3 years ago

4 0

It happens bro, don’t fret too much on it. You’ll find someone better

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Which of the following is a surface event that takes place during the rock cycle? Erosion Melting Metamorphosis Tectonic process

pshichka [43]

Which of the following is a surface event that takes place during the rock cycle? Erosion

6 0

3 years ago

Read 2 more answers

Which of these forces are acting within a nucleus? Check all that apply.

hjlf

Answer: strong nuclear forces and electrostatic forces of repulsion

Explanation:

8 0

3 years ago

The exponents in the rate law of an elementary step are always equal to the coefficients of each species in the balanced reactio

Naya [18.7K]

Answer:

True

Explanation:

True. Since in an elementary step , the reaction procedes by collision of the atoms of reactants involved and since the rate of collision is proportional to the concentration of each atom that participates in the elementary step , the exponents in the rate law of the elementary step always coincides with the coefficients that correspond to that reaction ( regardless if is unimolecular, bimolecular or trimolecular).

7 0

3 years ago

Calculating the Molecular Weight and Subunit Organization of a Protein From Its Metal Content The element molybdenum (atomic wei

Deffense [45]

Answer:

Dimer of two peptide chains with 1 mole of molybdenum metal each.

Explanation:

Percentage of molybdenum in protein = 0.08%

Molecular mass of nitrate reductase = 240,000 g

Mass of molybdenum = x

$0.08\%=\frac{x}{240,000 g}\times 100=192 g$

Moles of molybdenum = $\frac{192 g}{95.95 g/mol}=2.00 mol$

Each peptide chain of nitrate reductase contain 1 mole of molybdenum.

This means that nitrate reductase is composed of to two peptide chains. And in each peptide there is a single mole of molybdenum metal.

4 0

4 years ago

When 15.0 mL of a 6.42×10-4 M sodium sulfide solution is combined with 25.0 mL of a 2.39×10-4 M manganese(II) acetate solution d

Artist 52 [7]

Answer:

Q = 3.59x10⁻⁸

Yes, precipitate is formed.

Explanation:

The reaction of Na₂S with Mn(CH₃COO)₂ is:

Na₂S(aq) + Mn(CH₃COO)₂(aq) ⇄ MnS(s) + 2 Na(CH₃COO)(aq).

The solubility product of the precipitate produced, MnS, is:

MnS(s) ⇄ Mn²⁺(aq) + S²⁻(aq)

And Ksp is:

Ksp = 1x10⁻¹¹= [Mn²⁺] [S²⁻]

Molar concentration of both ions is:

[Mn²⁺] = 0.015Lₓ (6.42x10⁻⁴mol / L) / (0.015 + 0.025)L = 2.41x10⁻⁴M

[S²⁻] = 0.025Lₓ (2.39x10⁻⁴mol / L) / (0.015 + 0.025)L = 1.49x10⁻⁴M

Reaction quotient under these concentrations is:

Q = [2.41x10⁻⁴M] [1.49x10⁻⁴M]

Q = 3.59x10⁻⁸

As Q > Ksp, the equilibrium will shift to the left producing MnS(s) the precipitate

8 0

4 years ago