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Snezhnost [94]
3 years ago
7

Which of these forces are acting within a nucleus? Check all that apply.

Chemistry
1 answer:
hjlf3 years ago
8 0

Answer: strong nuclear forces and electrostatic forces of repulsion

Explanation:

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When 1.14 g of octane (molar mass = 114 g/mol) reacts with excess oxygen in a constant volume calorimeter, the temperature of th
maxonik [38]
I can't answer this question without knowing what the specific heat capacity of the calorimeter is. Luckily, I found a similar problem from another website which is shown in the attached picture. 

Q = nCpΔT
Q = (1.14 g)(1 mol/114 g)(6.97 kJ/kmol·°C)(10°C)(1000 mol/1 kmol)
<em>Q = +6970 kJ</em>

8 0
3 years ago
. True or False Viruses can range from the common cold to something like Ebola which can be deadly
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Answer:

True

Explanation:

learned it from class on a video

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3 years ago
Suppose 40.8g of copper(II) acetate is dissolved in 200.mL of a 0.70 M aqueous solution of sodium chromate.
Contact [7]

Answer:

0.42 M

Explanation:

The reaction that takes place is:

  • Cu(CH₃COO)₂ + Na₂CrO₄ → Cu(CrO₄) + 2Na(CH₃COO)

First we <u>calculate the moles of Na₂CrO₄</u>, using the <em>given volume and concentration</em>:

(200 mL = 0.200L)

  • 0.70 M * 0.200 L = 0.14 moles Na₂CrO₄

Now we <u>calculate the moles of Cu(CH₃COO)₂</u>, using its <em>molar mass</em>:

  • 40.8 g ÷ 181.63 g/mol = 0.224 mol Cu(CH₃COO)₂

Because the molar ratio of Cu(CH₃COO)₂ and Na₂CrO₄ is 1:1, we can directly <u>substract the reacting moles of Na₂CrO₄ from the added moles of Cu(CH₃COO)₂</u>:

  • 0.224 mol - 0.14 mol = 0.085 mol

Finally we <u>calculate the resulting molarity</u> of Cu⁺², from the <em>excess </em>cations remaining:

  • 0.085 mol / 0.200 L = 0.42 M

4 0
3 years ago
One of relatively few reactions that takes place directly between two solids at room temperature is Ba(OH)2 · 8H2O + ammonium th
Hatshy [7]

Answer:

\boxed{\text{3.1 g}}

Explanation:

We will need an equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:           315.46               76.12

           Ba(OH)₂·8H₂O + 2NH₄SCN ⟶ Ba(SCN)₂ + 2NH₃ + 10H₂O

m/g:             6.5

1. Moles of Ba(OH)₂·8H₂O

\text{Moles of Ba(OH)$_{2}\cdot $8H$_{2}$O}\\= \text{ 6.5 g Ba(OH)$_{2}\cdot $8H$_{2}$O} \times \dfrac{\text{1 mol Ba(OH)$_{2}\cdot $8H$_{2}$O}}{\text{ 315.46 g Ba(OH)$_{2}\cdot $8H$_{2}$O}}\\= \text{0.0206 mol Ba(OH)$_{2}\cdot $8H$_{2}$O}

2. Moles of NH₄SCN

The molar ratio is 2 mol NH₄SCN:1 mol Ba(OH)₂·8H₂O

\text{Moles of NH$_{4}$SCN} =\text{0.0206 mol Ba(OH)$_{2}\cdot $8H$_{2}$O} \times \dfrac{\text{2 mol NH$_{4}$SCN}}{\text{1 mol Ba(OH)$_{2}\cdot $8H$_{2}$O}}\\= \text{0.0412 mol NH$_{4}$SCN}

3. Mass of NH₄SCN

\text{Mass of NH$_{4}$SCN} = \text{0.0412 mol NH$_{4}$SCN} \times \dfrac{\text{76.12 g NH$_{4}$SCN}}{\text{1 mol NH$_{4}$SCN}} =\\\textbf{3.1 g NH$_{4}$SCN}\\\\\text{You must use }\boxed{\textbf{3.1 g}}\text{ NH$_{4}$SCN}

5 0
4 years ago
What group of elements on the periodic table are already chemically stable?
AlladinOne [14]
Anything in group 18. These are the noble gases, known for having the stable octet in the outermost electron shell (with the exception of Helium). These elements include Neon, Xenon, and Radon, to name a few.
7 0
4 years ago
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