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3 years ago

Consider functions f and g defined by the graph and the table. Please help me ASAP

Mathematics

1 answer:

Fed [463]3 years ago

3 0

Answer:

Step-by-step explanation:

Given are two functions represented one by graph and another by table

We can check the given statement one by one

1) $f(2)=18 : f(0) =15$

Average rate of change = $\frac{18-15}{2-0} =1.5$

For g(x) avg rate of change

= $\frac{g(2)-g(0)}{2-0} \\=4$

Hence g has a higher average rate of change than f.

True

2)f is linear and eventually exceeds g (f(0)>g(0) . True

3) True because y intercept is 10 for f while 8 for g

4) True because f(3) <g(3)

5) False both cannot be linear

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2 years ago

The area of a rectangle is 30 square root 3750 square inches, and the length is 3 square root 250 inches what is the width of th

Ann [662]

Answer:

$width=10\sqrt{15}\ in$

Step-by-step explanation:

-A rectangle's area is given by:

$A=lw\\\\l=length\\w=width$

Given A= $30\sqrt{3750}$ and $l=3\sqrt{250}$ , we substitute in the formula to solve for the width as follows:

$A=lw\\\\30\sqrt{3750}=3\sqrt{250}\times w\\\\w=\frac{30\sqrt{3750}}{3\sqrt{250}}\\\\w=10\frac{\sqrt{3750}}{\sqrt{250}}\\\\=10\times \sqrt{\frac{3750}{250}}\\\\=10\sqrt{15}\ in$

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3 years ago

Two chemicals A and B are combined to form a chemical C. The rate, or velocity, of the reaction is proportional to the product o

Keith_Richards [23]

Answer:

32.1 g

Step-by-step explanation:

In each 3 grams of C, there are 2 grams of A and 1 gram of B. So, for some amount C, the amount remaining of A is 40 -(2C/3), and the amount remaining of B is (50 -C/3). Since the reaction rate is proportional to the product of these amounts, we have ...

C' = k(40 -2C/3)(50 -C/3) = (2k/9)(60 -C)(150 -C) . . . for some constant k

This is separable differential equation with a solution of the form ...

ln((150 -C)/(60 -C)) = at + b

We know that C(0) = 0, so b=ln(150/60) = ln(2.5). And we know that C(10) = 20, so ln(130/40) = 10a +ln(2.5) ⇒ a = ln(1.3)/10

Then our equation for C is ...

ln((150 -C)/(60 -C)) = t·ln(1.3)/10 +ln(2.5)

For t=20, this is ...

ln((150 -C)/(60 -C)) = 2ln(1.3) +ln(2.5) = ln(2.5·1.3²) = ln(4.225)

Taking antilogs, we have ...

(150 -C)/(60 -C) = 4.225

1 +90/(60 -C) = 4.225

C = 60 -90/3.225 ≈ 32.093 . . . . . grams of product in 20 minutes

In 20 minutes, about 32.1 grams of C are formed.

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3 years ago

The martins car traveled 468 miles on 18 gallons of gas. Their car averaged how many miles per gallon.

hichkok12 [17]

Answer: 26

Step-by-step explanation: you divide 468 and 18 and you get 26.

3 0

3 years ago

I need help solving this

ozzi

Answer:

I have tried my best.

Hope this will help you.

Explanation is given in the above photo.

4 0

2 years ago