All categories

3 years ago

What number can be expressed as a nonrepeating, nonterminating decimal?

Mathematics

2 answers:

EastWind [94]3 years ago

8 0

An irrational number.

Happy studying!

Artyom0805 [142]3 years ago

7 0

Irrational numbers like

$\sqrt{2}=1.414..\\ e=2.718...\\ \pi=3.1415...\\ \phi=1.618...\\log(2)=0.3010..$

You might be interested in

If Ashley had 4 yards of yarn in Ramen had 11 feet of yarn who had more yarn

Greeley [361]

Answer: Ashley had more yarn, 1 yard = 3 ft 3 times 4 = 12 so 3 yards is 12 feet.

Step-by-step explanation:

5 0

3 years ago

The numbers below show a pattern 0.006 0.6 6

Ivenika [448]

Answer:

Yes

Step-by-step explanation:

The decimal points moves to the right at a constant pace.

0.006 -> 0.06 -> 0.6 -> 6

In other words, we are just multiplying each one by 10 to get the next value.

Best of Luck!

7 0

3 years ago

65/1000 in simplest form

Rudiy27

13/200 is the simplest form

4 0

3 years ago

Read 2 more answers

If p is true and q is false, then p ∨ q is true. <br> A. True<br> B. False

Marysya12 [62]

Answer:

no its false because p v q can only be true if both are true

Step-by-step explanation:

7 0

3 years ago

Gravel is being dumped from a conveyor belt at a rate of 20 ft3 /min and its coarseness is such that it forms a pile in the shap

pantera1 [17]

Answer:

The height of the pile is increasing at the rate of $\mathbf{ \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

Step-by-step explanation:

Given that :

Gravel is being dumped from a conveyor belt at a rate of 20 ft³ /min

i.e $\dfrac{dV}{dt}= 20 \ ft^3/min$

we know that radius r is always twice the diameter d

i.e d = 2r

Given that :

the shape of a cone whose base diameter and height are always equal.

then d = h = 2r

h = 2r

r = h/2

The volume of a cone can be given by the formula:

$V = \dfrac{\pi r^2 h}{3}$

$V = \dfrac{\pi (h/2)^2 h}{3}$

$V = \dfrac{1}{12} \pi h^3$

$V = \dfrac{ \pi h^3}{12}$

Taking the differentiation of volume V with respect to time t; we have:

$\dfrac{dV}{dt }= (\dfrac{d}{dh}(\dfrac{\pi h^3}{12})) \times \dfrac{dh}{dt}$

$\dfrac{dV}{dt }= (\dfrac{\pi h^2}{4} ) \times \dfrac{dh}{dt}$

we know that:

$\dfrac{dV}{dt}= 20 \ ft^3/min$

So;we have:

$20= (\dfrac{\pi (15)^2}{4} ) \times \dfrac{dh}{dt}$

$20= 56.25 \pi \times \dfrac{dh}{dt}$

$\mathbf{\dfrac{dh}{dt}= \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

The height of the pile is increasing at the rate of $\mathbf{ \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

8 0

3 years ago