Answer:
$14,747,642
Explanation:
Data provided in the question
Issued amount = $15,000,000
Coupon rate = 7.8%
Time period = 20 years
Yield to maturity is 8%
So for computing the carrying value of the bonds
First we have to compute the discount amortization for 3 years which is shown below:
= ($15,000,000 - $14,703,108) ÷ 20 years × 3 years
= $44,533.80
So, the carrying value of the bonds
= $14,703,108 + $44,533.80
= $14,747,642
Answer:
By mastering professional communication, the potential for misunderstandings occurring can be minimised. When you work in a team, you need to be able to regularly communicate with others. You need to listen to other people's ideas, whilst being able to clearly and effectively communicate your own.
Purposes:
The five purposes for communication are to inform, imagine, influence, meet social expectations and express feelings.
1) demand deposit account.
2) Computer software.
3) Saved for emergencies.
4) A job.
5) It's far more difficult to manage an account electronically.
6) Checks written after the statement closing date wouldn't appear on the statement.
7) When a check is drawn for more than the balance, the rest comes from a credit card account.
8) The account holder does not need to record the amount of the purchase in his or her check register.
9) All the above.
10) Easier.
Po = 0.5385, Lq = 0.0593 boats, Wq = 0.5930 minutes, W = 6.5930 minutes.
<u>Explanation:</u>
The problem is that of Multiple-server Queuing Model.
Number of servers, M = 2.
Arrival rate,
= 6 boats per hour.
Service rate,
= 10 boats per hour.
Probability of zero boats in the system,
= 0.5385
<u>Average number of boats waiting in line for service:</u>
Lq =![[\lambda.\mu.( \lambda / \mu )M / {(M – 1)! (M. \mu – \lambda )2}] x P0](https://tex.z-dn.net/?f=%5B%5Clambda.%5Cmu.%28%20%5Clambda%20%2F%20%5Cmu%20%29M%20%2F%20%7B%28M%20%E2%80%93%201%29%21%20%28M.%20%5Cmu%20%E2%80%93%20%5Clambda%20%292%7D%5D%20x%20P0)
=
= 0.0593 boats.
The average time a boat will spend waiting for service, Wq = 0.0593 divide by 6 = 0.009883 hours = 0.5930 minutes.
The average time a boat will spend at the dock, W = 0.009883 plus (1 divide 10) = 0.109883 hours = 6.5930 minutes.