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nekit [7.7K]
3 years ago
6

A company sells widgets. The amount of profit, y, made by the company, is related to

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
6 0

Answer:

-335230

Step-by-step explanation:

thats the answer

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Please help I just need the height and area of the triangle 6th grade math
Vesna [10]

Answer:

It looks like you forgot to attach a picture.

Since I cannot answer you're question fully, it will not be a complete solution.

The formula for the area of a triangle is \frac{1}{2} b \cdot h.

Just substitute you're base and height values.

Hope this helps!!!

5 0
3 years ago
If the discriminate of a quadratic equation is 28 describe the roots
katrin2010 [14]
B) two real roots is the answer because it is bigger than 0.
7 0
4 years ago
Find all the powers of 3 that are in the range 3 through 1000
Ksivusya [100]
So just use a calculator but here goes
3^1=3
3^2=9
3^3=27
3^4=81
3^5=243
3^6=729

and 3^7 is 2187 which is excluded











8 0
3 years ago
Find the value of x and y so that both proportions will be correct:
andrew11 [14]

The values of x and y are 0.2 and 0.4 respectively.

<em><u>Explanation</u></em>

The given proportions are.....

x: 1\frac{2}{3}=y: 3\frac{1}{3} and y:1.5=0.2:0.75

From the second proportion, we will get....

y:1.5=0.2:0.75\\ \\ \frac{y}{1.5}=\frac{0.2}{0.75} \\ \\ 0.75y=0.2*1.5\\ \\ 0.75y=0.3\\ \\ y=\frac{0.3}{0.75}=0.4

Now, we will plug this y=0.4 into the first proportion. So we will get....

x: 1\frac{2}{3}=y: 3\frac{1}{3}\\ \\ x: \frac{5}{3}=0.4:\frac{10}{3} \\ \\ \frac{x}{\frac{5}{3}}= \frac{0.4}{\frac{10}{3}}\\ \\ \frac{3x}{5}=\frac{1.2}{10}\\ \\ 30x=6\\ \\ x= \frac{6}{30}=0.2

So, the values of x and y are 0.2 and 0.4 respectively.

6 0
3 years ago
Consider the quadratic equation ax^2+bx+5=0,where a, b and c are rational numbers and the quadratic has two distinct zeros.
FrozenT [24]
You have shared the situation (problem), except for the directions:  What are you supposed to do here?  I can only make a educated guesses.  See below:

Note that if    <span>ax^2+bx+5=0    then it appears that c = 5 (a rational number).

Note that for simplicity's sake, we need to assume that the "two distinct zeros" are real numbers, not imaginary or complex numbers.  If this is the case, then the discriminant,    b^2 - 4(a)(c), must be positive.  Since c = 5, 

b^2 - 4(a)(5) > 0, or b^2 - 20a > 0.

Note that if the quadratic has two distinct zeros, which we'll call "d" and "e," then 

(x-d) and (x-e) are factors of ax^2 + bx + 5 = 0, and that because of this fact,

         - b plus sqrt( b^2 - 20a )
d =  ------------------------------------
                      2a

and

 </span>         - b minus sqrt( b^2 - 20a )
e =  ------------------------------------
                      2a

Some (or perhaps all) of these facts may help us find the values of "a" and "b."  Before going into that, however, I'm asking you to share the rest of the problem statement.  What, specificallyi, were you asked to do here?

7 0
3 years ago
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