Answer:
Solid will sublime into a gas.
Explanation:
Triple point is a temperature where the three states of a substance coexist.
If the pressure is lower than the triple point, the substance does not exist as a liquid, so it is impossible that solid melts, or that the solid remains as a solid.
Liquid state is not stable.
Answer:
person and earth since they are closer to the core ? maybe
A water molecule, abbreviated as H2O, is an example of a polar covalent bond. The electrons are unequally shared, with the oxygen atom spending more time with electrons than the hydrogen atoms. Since electrons spend more time with the oxygen atom, it carries a partial negative charge.
The answer would be D. This is because you cross-cross the charges.
Explanation:
![ClO^-(aq)+H_2O(l) \rightarrow HClO (aq)+OH^-(aq)\ [fast]](https://tex.z-dn.net/?f=ClO%5E-%28aq%29%2BH_2O%28l%29%20%5Crightarrow%20HClO%20%28aq%29%2BOH%5E-%28aq%29%5C%20%5Bfast%5D)
![I^-(aq)+HClO(aq) \rightarrow HIO(aq)+Cl^-(aq)\ [slow]](https://tex.z-dn.net/?f=I%5E-%28aq%29%2BHClO%28aq%29%20%5Crightarrow%20HIO%28aq%29%2BCl%5E-%28aq%29%5C%20%5Bslow%5D)
![OH^-(aq)+HIO(aq) \rightarrow H_2O(l)+IO^-(aq)\ [fast]](https://tex.z-dn.net/?f=OH%5E-%28aq%29%2BHIO%28aq%29%20%5Crightarrow%20H_2O%28l%29%2BIO%5E-%28aq%29%5C%20%5Bfast%5D)
(a)
Cancelling common terms, the overall reaction is as follows:
![ClO^-(aq)+I^-(aq) \rightarrow Cl^- (aq)+IO^-(aq)](https://tex.z-dn.net/?f=ClO%5E-%28aq%29%2BI%5E-%28aq%29%20%5Crightarrow%20Cl%5E-%20%28aq%29%2BIO%5E-%28aq%29)
(b)
Chemical species which are generated and consumed during the reaction are called intermediates. Therefore, in the given reaction, HClO(aq), OH-(aq) and HIO(aq) are intermediate species.
(c)
two reactant molecules are involved in each steps, therefore, each steps are bimolecular. Since water is in excess, therefore will not be rate law
Rate law for first step:
![rate=k_1[ClO^-]](https://tex.z-dn.net/?f=rate%3Dk_1%5BClO%5E-%5D)
Rate law for second step:
![rate=k_2 [I^-][HClO]](https://tex.z-dn.net/?f=rate%3Dk_2%20%5BI%5E-%5D%5BHClO%5D)
Rate law for third step:
![rate=k_3[OH^-][HIO]](https://tex.z-dn.net/?f=rate%3Dk_3%5BOH%5E-%5D%5BHIO%5D)
(d)
Step 2 is slow step, therefore this step will be rate determining step.
So, rate = k [I-] [HClO]
So, it consisted with the actual rate law