The common difference of the sequence is -3 and the fifth term is 5
<h3>How to determine the common difference?</h3>
The sequence is given as:
17, 14, 11, 8....
The common difference is
d = T2 - T1
So, we have
d = 14 - 17
Evaluate
d = -3
Hence, the common difference of the sequence is -3
<h3>How to determine the
fifth term?</h3>
The fifth term is calculated as:
T5 = a + 4d
Where
a = T1 = 17
d = -3
So, we have:
T5 = 17 - 4 * 3
Evaluate
T5 = 5
Hence, the fifth term is 5
<h3>How to determine the
nth term?</h3>
The nth term is calculated as:
Tn = a + (n - 1)d
Hence, the nth term is Tn = a + (n - 1)d
Read more about arithmetic sequence at:
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Answer:
60,912 ounce
Step-by-step explanation:
Answer:
d. 30
Step-by-step explanation:
The computation of the 35th percentile of this data set is shown below:
Before that first we have to series the number in ascending number
S. No Numbers
1 26
2 29
3 30
4 30
5 31
6 32
7 34
8 35
9 36
Now use the formula
Here n = 9
Percentile = 100
= 3.5th
= 3th + 0.5 (4th - 3th)
= 3th + 0.5 (30 - 30)
= 3th + 0
= 30
Now, the average cost per night is 495....for 5 nights, it is (495 * 5) = 2475
and since the cost has tripled in the past 4 years....we can divide the regular cost by 3 to find out how much it would have cost 4 years ago
2475/3 = 825..thats for a 5 night stay 4 yrs ago
so the difference is : 2475 - 825 = 1650