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Mashutka [201]
3 years ago
7

3. Let the pen return to its vertical position and suddenly pull the thread.

Physics
1 answer:
Softa [21]3 years ago
4 0

Answer:

The thread will experience a force on it .

Explanation:

When thread is tied to pen it will experience force. Because the pen is Abit heavy , there is a force that is applied to it which will cause it to elongate , after a while the thread will stretch, elongate and can later experience deformation. When it experience that, the thread can break after deformation and it has losses it elasticity.

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If a 25kg mass is dropped from a height of 5 meters what’s the work done by gravity
Elanso [62]

Answer:

Explanation:

M = 25kg

h = 5m

g = 9.8m/s2

Work done = mgh

Work done = 25 x 9.8 x 5

Work done = 1225J

8 0
3 years ago
Anyones good in gr5 science pls help me
oee [108]

Answer:

1. A

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6 0
3 years ago
You don;t run across elastic collision in real life
pentagon [3]

Answer:

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Explanation:

4 0
3 years ago
The rotor blades of a helicopter on the ground with its engine idling rotate at 48rpm. If it takes 12s for the pilot to increase
zhannawk [14.2K]

Answer:

α = 3.59 [rad/s^2]]

Explanation:

First we have to convert the values of the angular speeds of revolutions per minute to radians on second.

wf = final angular velocity = 460 [rpm]

wo= initial velocity = 48 [rpm]

t = time = 12 [s]

460 [\frac{rev}{min}]* [\frac{2\pi rad}{1 rev} ]*[\frac{1min}{60seg} ] = 48.17[\frac{rad}{s} ]\\48 [\frac{rev}{min}]* [\frac{2\pi rad}{1 rev} ]*[\frac{1min}{60seg} ] = 5.02[\frac{rad}{s} ]

now we can replace, in the following equation:

w_{o}=w_{i} +\alpha  *t\\where:\\\alpha = angular acceleration [rad/s^{2}]\\replacing:\\\alpha =\frac{w_{o} -w_{i} }{t} \\\alpha alpha =\frac{48.17-5.02 }{12} \\\alpha =3.59[\frac{rad}{s^{2} } ]

5 0
3 years ago
Consider two identical electric bulbs of power P and resistance R. You connect them to a battery of voltage V. The first time yo
natulia [17]

Answer:

The answer is 2X as much illumination as connection in series

Explanation:

We are given from the question that the two bulbs are identical in power and resistance.

Firstly we know that In a series connection the Voltage across the circuit elements are different whereas In a parallel connection, the same value of voltage passes through all the circuit elements.

Power is expressed as ;

P = V^2/ R

An increase in voltage leads to an increase in power likewise if the voltage is reduced the power also reduces.

The two bulbs are said to be having the same resistances , so the voltage across them in a series connection will be halved

V =1/2V1 + 1/2 V2; making the illumination across them to be low.

Therefore in parallel the illumination will be twice as much the illumination when connected in series.

4 0
4 years ago
Read 2 more answers
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