Answer:
1. A
sound can't travel through vacuum only
Answer:
α = 3.59 [rad/s^2]]
Explanation:
First we have to convert the values of the angular speeds of revolutions per minute to radians on second.
wf = final angular velocity = 460 [rpm]
wo= initial velocity = 48 [rpm]
t = time = 12 [s]
![460 [\frac{rev}{min}]* [\frac{2\pi rad}{1 rev} ]*[\frac{1min}{60seg} ] = 48.17[\frac{rad}{s} ]\\48 [\frac{rev}{min}]* [\frac{2\pi rad}{1 rev} ]*[\frac{1min}{60seg} ] = 5.02[\frac{rad}{s} ]](https://tex.z-dn.net/?f=460%20%5B%5Cfrac%7Brev%7D%7Bmin%7D%5D%2A%20%5B%5Cfrac%7B2%5Cpi%20rad%7D%7B1%20rev%7D%20%5D%2A%5B%5Cfrac%7B1min%7D%7B60seg%7D%20%5D%20%3D%2048.17%5B%5Cfrac%7Brad%7D%7Bs%7D%20%5D%5C%5C48%20%5B%5Cfrac%7Brev%7D%7Bmin%7D%5D%2A%20%5B%5Cfrac%7B2%5Cpi%20rad%7D%7B1%20rev%7D%20%5D%2A%5B%5Cfrac%7B1min%7D%7B60seg%7D%20%5D%20%3D%205.02%5B%5Cfrac%7Brad%7D%7Bs%7D%20%5D)
now we can replace, in the following equation:
![w_{o}=w_{i} +\alpha *t\\where:\\\alpha = angular acceleration [rad/s^{2}]\\replacing:\\\alpha =\frac{w_{o} -w_{i} }{t} \\\alpha alpha =\frac{48.17-5.02 }{12} \\\alpha =3.59[\frac{rad}{s^{2} } ]](https://tex.z-dn.net/?f=w_%7Bo%7D%3Dw_%7Bi%7D%20%2B%5Calpha%20%20%2At%5C%5Cwhere%3A%5C%5C%5Calpha%20%3D%20angular%20acceleration%20%5Brad%2Fs%5E%7B2%7D%5D%5C%5Creplacing%3A%5C%5C%5Calpha%20%3D%5Cfrac%7Bw_%7Bo%7D%20-w_%7Bi%7D%20%7D%7Bt%7D%20%5C%5C%5Calpha%20alpha%20%3D%5Cfrac%7B48.17-5.02%20%7D%7B12%7D%20%5C%5C%5Calpha%20%3D3.59%5B%5Cfrac%7Brad%7D%7Bs%5E%7B2%7D%20%7D%20%5D)
Answer:
The answer is 2X as much illumination as connection in series
Explanation:
We are given from the question that the two bulbs are identical in power and resistance.
Firstly we know that In a series connection the Voltage across the circuit elements are different whereas In a parallel connection, the same value of voltage passes through all the circuit elements.
Power is expressed as ;
P = V^2/ R
An increase in voltage leads to an increase in power likewise if the voltage is reduced the power also reduces.
The two bulbs are said to be having the same resistances , so the voltage across them in a series connection will be halved
V =1/2V1 + 1/2 V2; making the illumination across them to be low.
Therefore in parallel the illumination will be twice as much the illumination when connected in series.
