The force acting on the electron is 0.57*10^(-17) N.
The force on the electron is calculated by the Lauren law.
F=BQvsinθ
F=0.10*〖10〗^(-4)*1.6*〖10〗^(-19)*2.5*10^(6)sin35°
=0.57*10^(-17) N
Therefore the force on the electron is 0.57*10^(-17) N
The acceleration due to gravity near the surface of the planet is 27.38 m/s².
<h3>
Acceleration due to gravity near the surface of the planet</h3>
g = GM/R²
where;
- G is universal gravitation constant
- M is mass of the planet
- R is radius of the planet
- g is acceleration due to gravity = ?
g = (6.626 x 10⁻¹¹ x 2.81 x 5.97 x 10²⁴) / (6371 x 10³)²
g = 27.38 m/s²
Thus, the acceleration due to gravity near the surface of the planet is 27.38 m/s².
Learn more about acceleration due to gravity here: brainly.com/question/88039
#SPJ1
Answer:
Elastic and Inelastic Collisions. A perfectly elastic collision is defined as one in which there is no loss of kinetic energy in the collision. An inelastic collision is one in which part of the kinetic energy is changed to some other form of energy in the collision.