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Sedaia [141]
4 years ago
10

Observation and experimentation have led many scientists to accept a theory about the origin of the universe, called The Big Ban

g Theory. Briefly describe one piece of evidence that supports this scientific theory. (4 points)
Chemistry
2 answers:
34kurt4 years ago
4 0
Red shift is one piece of observational evidence which supports the big bang theory. The fact that galaxies are moving away from us means that the universe was once much smaller, supporting the big bang theory which states that all the matter in the universe once occupied a single point with infinite density.
Anna71 [15]4 years ago
4 0

Answer:

The Big Bang Theory is the dominant cosmological theory about the early development of the universe. Cosmologists use the term "Big Bang" to refer to the idea that the universe was originally very hot and dense at some finite time in the past. Since then it has cooled by expansion to the current diluted state and continues to expand today. The theory is supported by more complete and precise explanations from available scientific evidence and observation. According to the best measurements available in 2010, the initial conditions occurred approximately 13.3 or 13.9 billion years ago.

In general, three empirical evidences that support the cosmological theory of the Big Bang are considered. These are: the expansion of the universe that is expressed in Hubble's law and that can be seen in the redshift of galaxies, the detailed measurements of the cosmic microwave background, and the abundance of light elements. In addition, the correlation function of the large-scale structure of the universe fits with the Big Bang theory.

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Answer:

ΔH = -20kJ

Explanation:

The enthalpy of formation of a compound is defined as the change of enthalpy during the formation of 1 mole of the substance from its constituent elements. For H₂S(g) the reaction that describes this process is:

H₂(g) + S(g) → H₂S(g)

Using Hess's law, it is possible to sum the enthalpies of several reactions to obtain the change in enthalpy of a particular reaction thus:

<em>(1) </em>H₂S(g) + ³/₂O₂(g) → SO₂(g) + H₂O(g) ΔH = -519 kJ

<em>(2) </em>H₂(g) + ¹/₂O₂(g) → H₂O(g) ΔH = -242 kJ

<em>(3) </em>S(g) + O₂(g) → SO₂(g) ΔH = -297 kJ

The sum of -(1) + (2) + (3) gives:

<em>-(1) </em>SO₂(g) + H₂O(g) → H₂S(g) + ³/₂O₂(g) ΔH = +519 kJ

<em>(2) </em>H₂(g) + ¹/₂O₂(g) → H₂O(g) ΔH = -242 kJ

<em>(3) </em>S(g) + O₂(g) → SO₂(g) ΔH = -297 kJ

<em>-(1) + (2) + (3): </em><em>H₂(g) + S(g) → H₂S(g) </em>

<em>ΔH =</em> +519kJ - 242kJ - 297kJ = <em>-20 kJ</em>

<em />

I hope it helps!

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