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ivann1987 [24]
3 years ago
8

Factor completely. Remember to look first for a common factor. If a polynomial is prime, state this.

Mathematics
1 answer:
Yakvenalex [24]3 years ago
8 0
This one is prime.  The sum of two squares doesn't factor.

The more interesting case is q^2-1, which factors into (q-1)(q+1).  
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Kelly plans to put her graduation money into an account and leave it there for 4 years while she goes to college. she recieves $
Firlakuza [10]

Answer:

C) $877.50

Step-by-step explanation:

Time t = 4 years

Principal, p = $750

rate, r = 4.25% = 0.0425

Amount that will be in her account in four years =

Simple interest (prt/100) + principal

750 * 4.25* 4 / 100 + 750

127.5 + 750

= $877.50

7 0
3 years ago
Choose the best definition for the term: factor (1 point)
Molodets [167]
I would say number 2
3 0
3 years ago
Read 2 more answers
Asdasdasd
Amanda [17]

Answer: explanation

Step-by-step explanation:

1. answer:2592

explanation: it says to find the % of the small sample so 45 out of 75 is 60% then says to convert it into a decimal and multiply it by 4,320 which equals 2592.

2. answer:

explanation:540 is 12% of 4500. I don't quite understand what that number is but I'm assuming it's the percentage number and that number is 12 and that's 12% out of 100. if it means what percentage 540 is out of 100 then its 540%

3. answer:30
explanation: 4 out of 20 is 20% converted to decimal is 0.2 then multiply it by 15 0 and that adds to 30.

i hope this helped and i hope its correct

7 0
1 year ago
Please help, thanks if you do. (WILL MARK)
Likurg_2 [28]

Answer: n-6p^2 + 2np  

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Cos4theta+cos2theta/ cos4theta-cos2theta= _____
vovangra [49]

\bf \textit{Sum to Product Identities} \\\\ cos(\alpha)+cos(\beta)=2cos\left(\cfrac{\alpha+\beta}{2}\right)cos\left(\cfrac{\alpha-\beta}{2}\right) \\\\\\ cos(\alpha)-cos(\beta)=-2sin\left(\cfrac{\alpha+\beta}{2}\right)sin\left(\cfrac{\alpha-\beta}{2}\right) \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \cfrac{cos(4\theta )+cos(2\theta )}{cos(4\theta )-cos(2\theta )}\implies \cfrac{2cos\left( \frac{4\theta +2\theta }{2} \right)cos\left( \frac{4\theta -2\theta }{2} \right)}{-2sin\left( \frac{4\theta +2\theta }{2} \right)sin\left( \frac{4\theta -2\theta }{2} \right)} \implies \cfrac{cos\left( \frac{6\theta }{2} \right)cos\left( \frac{2\theta }{2} \right)}{-sin\left( \frac{6\theta }{2} \right)sin\left( \frac{2\theta }{2} \right)}

\bf \cfrac{cos(3\theta )cos(\theta )}{-sin(3\theta )sin(\theta )}\implies -\cfrac{cos(3\theta )}{sin(3\theta )}\cdot \cfrac{cos(\theta )}{sin(\theta )}\implies -cot(3\theta )cot(\theta )

8 0
3 years ago
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