To approximate the P(x<27) we need to find the z-score of the data, this will be given by:
z=(x-μ)/σ
where:
μ-mean
σ-standard deviation
x=27, μ=32, σ=4
z=(27-32)/4
z=-5/4
z=-1.25
thus
P(x<27)=P(z<-1.25)
=0.1056
=10.56%
Answer: 10.56%
The 3 inside angles of a triangle need to equal 180 degrees. Looking at the larger outside triangle the top angle is 30 and the lower right angle is 60.
30 + 60 = 90
The lower left angle needs to be 180 - 90 = 90 degrees.
That angle is split into two angles with one given as 70.
This means X needs to be 90 - 70 = 20 degrees.
x = 20
What a questions equals out to be.
Answer:
A. 
B. 
Step-by-step explanation:
Given that:
An investment of Amount = $8000
earns at an annual rate of interest = 7% = 0.07 compounded continuously
The objective is to :
A) Find the instantaneous rate of change of the amount in the account after 2 year(s).
we all know that:

where;

The instantaneous rate of change = 




At t = 2 years; the instantaneous rate of change is:


(B) Find the instantaneous rate of change of the amount in the account at the time the amount is equal to $12,000.
Here the amount = 12000



㏑(1.5) = 0.07 t
0.405465 = 0.07 t
t = 0.405465 /0.07
t = 5.79

At t = 5.79


Answer:
Algebra Examples
Popular Problems Algebra Graph f(x)=3x^2-5
f
(
x
)
=
3
x
2
−
5
Find the properties of the given parabola.
Tap for more steps...
Direction: Opens Up
Vertex:
(
0
,
−
5
)
Focus:
(
0
,
−
59
12
)
Axis of Symmetry:
x
=
0
Directrix:
y
=
−
61
12
Select a few
x
values, and plug them into the equation to find the corresponding
y
values. The
x
values should be selected around the vertex.
Tap for more steps...
x
y
−
2
7
−
1
−
2
0
−
5
1
−
2
2
7
Graph the parabola using its properties and the selected points.
Direction: Opens Up
Vertex:
(
0
,
−
5
)
Focus:
(
0
,
−
59
12
)
Axis of Symmetry:
x
=
0
Directrix:
y
=
−
61
12
x
y
−
2
7
−
1
−
2
0
−
5
1
−
2
2
7
image of graph
Step-by-step explanation: